To find the volume of a sphere, we use the formula:
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Given the diameter of the basketball is 9 inches, we first calculate the radius:
\[ r = \frac{\text{diameter}}{2} = \frac{9}{2} = 4.5 \text{ inches} \]
Now, we can plug the radius into the volume formula using \( \pi \approx 3.14 \):
\[ V = \frac{4}{3} \cdot 3.14 \cdot (4.5)^3 \]
Calculating \( (4.5)^3 \):
\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 20.25 \times 4.5 = 91.125 \]
Now, substituting \( 91.125 \) back into the volume formula:
\[ V = \frac{4}{3} \cdot 3.14 \cdot 91.125 \]
Calculating \( \frac{4}{3} \cdot 3.14 \):
\[ \frac{4}{3} \cdot 3.14 = 4.1867 \quad (\text{approximately}) \]
Now, multiply by 91.125:
\[ V \approx 4.1867 \cdot 91.125 \approx 381.5 \]
Thus, the volume of the basketball is approximately \( 381.5 \) cubic inches.
The answer is:
381.5 in.³ (or 381.5 inches cubed)
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