To solve this problem, let's use a proportional relationship.
Let \( b \) represent the number of students who choose band, and \( c \) represent the number of students who choose choir. According to the problem, we have:
-
The total number of students is 250:
\( b + c = 250 \) -
There are four times as many seats in choir as there are in band:
\( c = 4b \)
Now we can substitute the second equation into the first equation:
\[ b + 4b = 250 \]
This simplifies to:
\[ 5b = 250 \]
Now, we can solve for \( b \):
\[ b = \frac{250}{5} = 50 \]
So, the number of students who can choose band is \( \boxed{50} \).