Question

Question

There are 2 types of tickets to attend an awards dinner—silver and gold. The gold tickets are $8 more than the silver. If Patrick bought 10 tickets at each level and spent a total of $140, find the price of each ticket.(1 point)
$
for each silver ticket and $
for each gold ticket

Answer 1

Let the price of a silver ticket be \( x \) dollars. Then, the price of a gold ticket would be \( x + 8 \) dollars.

Patrick bought 10 silver tickets and 10 gold tickets, so the total cost can be expressed as follows:

\[ 10x + 10(x + 8) = 140 \]

Now, simplify the equation:

\[ 10x + 10x + 80 = 140 \] \[ 20x + 80 = 140 \]

Next, subtract 80 from both sides:

\[ 20x = 60 \]

Now, divide both sides by 20:

\[ x = 3 \]

So, the price of a silver ticket is \( x = 3 \) dollars. To find the price of a gold ticket:

\[ x + 8 = 3 + 8 = 11 \]

Thus, the price of each ticket is:

\[ \text{Silver ticket: } $3 \] \[ \text{Gold ticket: } $11 \]

The final answer is:

• Silver ticket: $3
• Gold ticket: $11