Question

The roof of a gazebo is in the shape of an octagonal pyramid. Each side of the octagon is 12 feet, the height of each triangular face is 10 feet, and the area of the octagon is 695 square feet. How many square feet of cedar are needed to cover the lateral surface area of the octagonal pyramid?(1 point)
Responses

360 ft.2
360 ft. squared

480 ft.2
480 ft. squared

1,175 ft.2
1,175 ft. squared

960 ft.2

1 answer

To find the lateral surface area of the octagonal pyramid, we need to calculate the area of the triangular faces that make up the sides of the pyramid.

  1. Determine the number of triangular faces: Since it's an octagonal pyramid, there are 8 triangular faces.

  2. Calculate the area of one triangular face: The area \( A \) of a triangle can be computed using the formula: \[ A = \frac{1}{2} \times \text{base} \times \text{height} \] In this case, the base of each triangular face is a side of the octagon, which is 12 feet, and the height of each triangular face is 10 feet. \[ A = \frac{1}{2} \times 12 \times 10 = \frac{120}{2} = 60 \text{ square feet} \]

  3. Calculate the total lateral surface area of the pyramid: Multiply the area of one triangular face by the number of triangular faces: \[ \text{Total lateral surface area} = 8 \times A = 8 \times 60 = 480 \text{ square feet} \]

Thus, the total lateral surface area of the octagonal pyramid is 480 square feet.

Therefore, the answer is: 480 ft.²