Question Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope?(1 point) Responses The newtons are in the same direction, so the newtons can be multiplied. The newtons are in the same direction, so the newtons can be multiplied. The forces are in the same direction, so the newtons can be added. The forces are in the same direction, so the newtons can be added. The forces are in opposite directions, so the newtons can be subtracted. The forces are in opposite directions, so the newtons can be subtracted. The forces are in opposite directions, so the newtons can be divided.

Answer 1

To determine the net force on the rope in a tug-of-war scenario, you need to consider the directions of the forces being applied. In this case, the forces are:

• Five children pulling with a force of 10 newtons each: \( 5 \times 10 , \text{N} = 50 , \text{N} \) (in one direction)
• Ten children pulling with a force of 15 newtons each: \( 10 \times 15 , \text{N} = 150 , \text{N} \) (in the opposite direction)

Since the forces are in opposite directions, you would subtract the smaller force from the larger force to find the net force.

Thus, the net force can be calculated as follows:

\[ \text{Net Force} = 150 , \text{N} - 50 , \text{N} = 100 , \text{N} \]

The correct response is: The forces are in opposite directions, so the newtons can be subtracted.