Question

Question

Solve 2x+10≥12 . Make sure to write your inequality so that x comes first.

Note: You will find the option to add a >
, <
, ≥
, or ≤
symbol in the Comparison (<)
keyboard.

(1 point)

Answer 1

To solve the inequality \( 2x + 10 \geq 12 \), we need to isolate \( x \) on one side of the inequality. Here are the steps to do that:

1. Subtract 10 from both sides of the inequality to eliminate the constant term on the left side:
\[ 2x + 10 - 10 \geq 12 - 10 \]
\[ 2x \geq 2 \]

2. Divide both sides by 2 to solve for \( x \):
\[ \frac{2x}{2} \geq \frac{2}{2} \]
\[ x \geq 1 \]

Therefore, the solution to the inequality \( 2x + 10 \geq 12 \) is \( x \geq 1 \).

Written so that \( x \) comes first, we have:
\[ x \geq 1 \]