Question Rewrite the irrational cube root ^

3^√ 189 as the product of an integer and another irrational cube root. Show your work.

1 answer

To rewrite the irrational cube root \( \sqrt[3]{189} \) as the product of an integer and another irrational cube root, we'll start by factoring 189 into its prime factors.

  1. Factor 189:

    • \( 189 = 3 \times 63 = 3 \times 3 \times 21 = 3^3 \times 7 \)
    • Therefore, \( 189 = 3^3 \times 7 \).
  2. Now, we can rewrite \( \sqrt[3]{189} \): \[ \sqrt[3]{189} = \sqrt[3]{3^3 \times 7} \]

  3. Apply the property of cube roots: \[ \sqrt[3]{189} = \sqrt[3]{3^3} \times \sqrt[3]{7} \]

  4. Since \( \sqrt[3]{3^3} = 3 \), we can express it as: \[ \sqrt[3]{189} = 3 \times \sqrt[3]{7} \]

Thus, the expression \( \sqrt[3]{189} \) can be rewritten as the product of an integer and another irrational cube root: \[ \sqrt[3]{189} = 3 \cdot \sqrt[3]{7} \]