To rearrange the formula for the area of a trapezoid \( A = \frac{1}{2}h(b_1 + b_2) \) to solve for \( h \), follow these steps:
-
Multiply both sides by \( 2 \) to eliminate the fraction:
\( 2A = h(b_1 + b_2) \) -
Divide by \( (b_1 + b_2) \) to isolate \( h \):
\( h = \frac{2A}{b_1 + b_2} \)
Thus, the rearranged formula for \( h \) is:
\[ h = \frac{2A}{b_1 + b_2} \]
So, the correct response is:
h is equal to the fraction with numerator 2A and denominator b1 + b2.