M0leswater*40.6kJ=5500kJ/hr*2hr
solve for moles water.
now, solve for liters water
moleswater*18gwater/mole*1liter/1000g=...liters of water.
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It has been determined that the body can generate 5500 kJ of energy during one hour of strenuous exercise. Perspiration is the body's mechanism for eliminating this heat. How many liters of water would have to be evaporated through perspiration to rid the body of the heat generated during two hours of exercise? (The heat of vaporization of water is 40.6 kJ/mol. Assume the density of water is 1.000 g/mL)
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1 answer