Question

Question

Luca is in a culvert below street level. He launches an object at an upward velocity of 40 feet per second. Use GeoGebra to graph the situation using the formula y=−16t2+40t−5
. How far above or below street level is Luca’s initial launching point?(1 point)
Responses

2.5 feet below
2.5 feet below

5 feet above
5 feet above

0 feet above or below
0 feet above or below

5 feet below
5 feet below
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Answer 1

To find out how far above or below street level Luca’s initial launching point is, we need to evaluate the function when \( t = 0 \).

The given formula is:

\[ y = -16t^2 + 40t - 5 \]

Substituting \( t = 0 \) into the formula:

\[ y = -16(0)^2 + 40(0) - 5 \] \[ y = -5 \]

Thus, when \( t = 0 \), \( y = -5 \).

This means that Luca’s initial launching point is 5 feet below street level.

So the correct response is:

5 feet below.