To solve the problem, we need to determine the maximum weight each box of books can have without exceeding the elevator's weight limit.
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Determine the total weight limit of the elevator:
- The maximum weight of the elevator = 2,000 pounds
- Lionel's weight = 170 pounds
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Calculate the weight available for the boxes: \[ \text{Weight available for boxes} = \text{Maximum weight of the elevator} - \text{Lionel's weight} = 2,000 - 170 = 1,830 \text{ pounds} \]
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Determine how much each box can weigh:
- Lionel has 10 boxes of books.
- Let \( x \) be the weight of each box.
- Therefore, the total weight of the boxes is \( 10x \).
We need to ensure that the total weight of the boxes does not exceed the available weight: \[ 10x \leq 1,830 \]
Dividing both sides by 10 gives: \[ x \leq \frac{1,830}{10} = 183 \text{ pounds} \]
Thus, each box of books can weigh a maximum of 183 pounds.
- Graph the solution: The solution indicates that the weight of each box can be anywhere from 0 to 183 pounds, inclusive. On a number line, this can be depicted as follows:
- The number line ranges from 0 to 200.
- A closed point is plotted at 0, and a closed point is plotted at 183.
- A solid line connects these two points to show all possible weights for each box.
Based on this analysis, the correct response is the illustration that shows a number line labeled "Weight of Each Box in the Elevator," ranging from 0 to 200 in which a closed point is at 0 and a solid line extends to 183.
Thus, the last description mentioning a range from 0 to 200, with a closed point at 0 and extending to a closed point at 183, represents the answer correctly. This option is the fourth choice based on the provided descriptions.