To set up the system of equations based on the given information:
-
Joelle's collection:
- Joelle starts with 18 rocks and gains 4 rocks each week.
- Let \( x \) be the number of weeks.
- The equation for Joelle's rocks is: \[ y = 4x + 18 \]
-
Lewis's collection:
- Lewis starts with 30 rocks and gains 3 rocks each week.
- The equation for Lewis's rocks is: \[ y = 3x + 30 \]
Now, let's fill in the responses based on these equations:
a) Joelle has \( y = 4x + 18 \).
b) Lewis has \( y = 3x + 30 \).
Next, to find out after how many weeks Joelle and Lewis will have the same number of rocks, we need to set their equations equal to each other:
\[ 4x + 18 = 3x + 30 \]
Now, solve for \( x \):
\[ 4x - 3x = 30 - 18 \] \[ x = 12 \]
c) After 12 weeks, Joelle and Lewis will have the same number of rocks.
Finally, we substitute \( x = 12 \) back into either equation to find out how many rocks they will each have at that time:
Using Joelle's equation: \[ y = 4(12) + 18 = 48 + 18 = 66 \]
Using Lewis's equation: \[ y = 3(12) + 30 = 36 + 30 = 66 \]
Thus, they will each have 66 rocks.
d) They will each have 66 rocks in their collection when their amounts are equal.
To summarize:
a) Joelle has \( y = 4x + 18 \).
b) Lewis has \( y = 3x + 30 \).
c) After 12 weeks.
d) They will each have 66 rocks in their collection.