Asked by Matt
Question:
gyazo.com/c8fe92564a8387ffc127233f6ad989a9
My work:
gyazo.com/27caca9994d03409268162130c61ce08
(I understand how to do trapezoidal approximation, but how would I go bout this while using only 4 sections?)
gyazo.com/c8fe92564a8387ffc127233f6ad989a9
My work:
gyazo.com/27caca9994d03409268162130c61ce08
(I understand how to do trapezoidal approximation, but how would I go bout this while using only 4 sections?)
Answers
Answered by
Matt
I realize I put 30 instead of 15. so the answer would actually be 2205!
When you solve using only 4 sections do you just ignore the other ones??
((f(0)+f(30))/2 * Δx) + ((f(30)+f(60))/2 * Δx) + ((f(60)+f(90))/2 * Δx) + ((f(90)+f(120))/2 * Δx)
(Δx)/(2) (f(0) + 2(f(30) + 2(f(60) + 2(f(90) + (f(120)
(30/2) (0+36 + 38 + 48 + 12)
A = 2010ft^2
When you solve using only 4 sections do you just ignore the other ones??
((f(0)+f(30))/2 * Δx) + ((f(30)+f(60))/2 * Δx) + ((f(60)+f(90))/2 * Δx) + ((f(90)+f(120))/2 * Δx)
(Δx)/(2) (f(0) + 2(f(30) + 2(f(60) + 2(f(90) + (f(120)
(30/2) (0+36 + 38 + 48 + 12)
A = 2010ft^2
Answered by
oobleck
You need to use 30, since you must cover the interval [0,120] with 4 subintervals. It just means that you use 2 width-15 intervals for each of your width-30 ones.
Your work looks good to me.
Your work looks good to me.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.