To determine for which values of \( x \) and \( y \) quadrilateral ABCD can be a parallelogram, we need to check the condition for a parallelogram: opposite sides must be equal in length.
Given:
- Side AB = \( 40x \)
- Side BC = \( 4 + 3y \)
- Side CD = \( 8x + 32 \)
- Side AD = \( 9y - 20 \)
For ABCD to be a parallelogram, the following must be true:
- \( AB = CD \)
- \( BC = AD \)
Let's set up the equations:
- \( 40x = 8x + 32 \)
- \( 4 + 3y = 9y - 20 \)
Now, let's solve each equation:
Solving the first equation:
\[ 40x = 8x + 32 \] Subtract \( 8x \) from both sides: \[ 32x = 32 \] Dividing both sides by 32 gives: \[ x = 1 \]
Solving the second equation:
\[ 4 + 3y = 9y - 20 \] Subtracting \( 3y \) from both sides: \[ 4 = 6y - 20 \] Adding 20 to both sides: \[ 24 = 6y \] Dividing both sides by 6 gives: \[ y = 4 \]
Conclusion
Using our results, we find: \[ x = 1 \quad \text{and} \quad y = 4 \]
Thus, the correct response is:
x equals 1 and y equals 4