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Original Question
Erik draws quadrilateral ABCD . If side AB=40x , side BC=4+3y , side CD=8x+32 , and side AD=9y−20 , for what values of x and y...Question
Question
Erik draws quadrilateral ABCD
. If side AB=40x
, side BC=4+3y
, side CD=8x+32
, and side AD=9y−20
, for what values of x and y can Erik be sure that his quadrilateral is a parallelogram?(1 point)
Responses
x=4
and y=1
x equals 4 and y equals 1
x=20
and y=8
x equals 20 and y equals 8
x=40
and y=16
x equals 40 and y equals 16
x=1
and y=4
x equals 1 and y equals 4
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Erik draws quadrilateral ABCD
. If side AB=40x
, side BC=4+3y
, side CD=8x+32
, and side AD=9y−20
, for what values of x and y can Erik be sure that his quadrilateral is a parallelogram?(1 point)
Responses
x=4
and y=1
x equals 4 and y equals 1
x=20
and y=8
x equals 20 and y equals 8
x=40
and y=16
x equals 40 and y equals 16
x=1
and y=4
x equals 1 and y equals 4
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Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine for which values of \( x \) and \( y \) quadrilateral ABCD can be a parallelogram, we need to check the condition for a parallelogram: opposite sides must be equal in length.
Given:
- Side AB = \( 40x \)
- Side BC = \( 4 + 3y \)
- Side CD = \( 8x + 32 \)
- Side AD = \( 9y - 20 \)
For ABCD to be a parallelogram, the following must be true:
1. \( AB = CD \)
2. \( BC = AD \)
Let's set up the equations:
1. \( 40x = 8x + 32 \)
2. \( 4 + 3y = 9y - 20 \)
Now, let's solve each equation:
### Solving the first equation:
\[
40x = 8x + 32
\]
Subtract \( 8x \) from both sides:
\[
32x = 32
\]
Dividing both sides by 32 gives:
\[
x = 1
\]
### Solving the second equation:
\[
4 + 3y = 9y - 20
\]
Subtracting \( 3y \) from both sides:
\[
4 = 6y - 20
\]
Adding 20 to both sides:
\[
24 = 6y
\]
Dividing both sides by 6 gives:
\[
y = 4
\]
### Conclusion
Using our results, we find:
\[
x = 1 \quad \text{and} \quad y = 4
\]
Thus, the correct response is:
**x equals 1 and y equals 4**
Given:
- Side AB = \( 40x \)
- Side BC = \( 4 + 3y \)
- Side CD = \( 8x + 32 \)
- Side AD = \( 9y - 20 \)
For ABCD to be a parallelogram, the following must be true:
1. \( AB = CD \)
2. \( BC = AD \)
Let's set up the equations:
1. \( 40x = 8x + 32 \)
2. \( 4 + 3y = 9y - 20 \)
Now, let's solve each equation:
### Solving the first equation:
\[
40x = 8x + 32
\]
Subtract \( 8x \) from both sides:
\[
32x = 32
\]
Dividing both sides by 32 gives:
\[
x = 1
\]
### Solving the second equation:
\[
4 + 3y = 9y - 20
\]
Subtracting \( 3y \) from both sides:
\[
4 = 6y - 20
\]
Adding 20 to both sides:
\[
24 = 6y
\]
Dividing both sides by 6 gives:
\[
y = 4
\]
### Conclusion
Using our results, we find:
\[
x = 1 \quad \text{and} \quad y = 4
\]
Thus, the correct response is:
**x equals 1 and y equals 4**
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