Question content area topPart 1Find the third​, fourth​, and eleventh terms of the sequence described by the rule.​A(n)equalsnegative 3plus​(nminus​1)(6​)Question content area bottomPart 1​A(3​)equalsenter your response here ​(Simplify your​ answer.)

Answer 1

To find the terms of the sequence described by the rule \( A(n) = -3 + (n-1)(6) \), we will substitute the values of \( n \) for the third, fourth, and eleventh terms.

1. Finding the third term \( A(3) \): \[ A(3) = -3 + (3-1)(6) \] \[ = -3 + (2)(6) \] \[ = -3 + 12 \] \[ = 9 \]

2. Finding the fourth term \( A(4) \): \[ A(4) = -3 + (4-1)(6) \] \[ = -3 + (3)(6) \] \[ = -3 + 18 \] \[ = 15 \]

3. Finding the eleventh term \( A(11) \): \[ A(11) = -3 + (11-1)(6) \] \[ = -3 + (10)(6) \] \[ = -3 + 60 \] \[ = 57 \]

Summary of Terms

• \( A(3) = 9 \)
• \( A(4) = 15 \)
• \( A(11) = 57 \)

Thus, the third term is \( 9 \), the fourth term is \( 15 \), and the eleventh term is \( 57 \).