To solve the inequality \((x - 6)^3 < 27\), we can start by simplifying it.
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Take the cube root of both sides: \[ x - 6 < 3 \] (since \(\sqrt[3]{27} = 3\))
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Solve for \(x\): \[ x < 3 + 6 \] \[ x < 9 \]
Therefore, the solution to the inequality is that \(x\) can take any value less than 9.
Now, we can express the solution in the required format:
Choice B is appropriate since it asks for the values of \(x\) in interval notation.
The interval representing the solution is: \[ (-\infty, 9) \]
So the final answer is:
B. The solutions are the values of \(x\) in the interval \((- \infty, 9)\).