To solve the problem, we need to find integer coordinates for point \( Q \) given that \( P = (-4, 7) \) and the length of \( PQ \) is 17 units. We can use Pythagorean triples to achieve this.
Step 1: Identify a suitable Pythagorean triple
A Pythagorean triple consists of three positive integers \( a, b, c \) such that \( a^2 + b^2 = c^2 \), where \( c \) is the hypotenuse. We are looking for a triple where \( c = 17 \).
One Pythagorean triple that includes \( 17 \) is \( (8, 15, 17) \).
Step 2: Use the Pythagorean triple
Using the triple \( (8, 15, 17) \):
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If we use \( 8 \) as the horizontal leg and \( 15 \) as the vertical leg, the coordinates of \( Q \) can be calculated as follows:
- The x-coordinate of \( Q \) would be \( x_P + 8 = -4 + 8 = 4 \).
- The y-coordinate of \( Q \) would be \( y_P + 15 = 7 + 15 = 22 \).
Thus, one possible coordinate for \( Q \) is \( (4, 22) \).
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Conversely, if we use \( 15 \) as the horizontal leg and \( 8 \) as the vertical leg, the coordinates of \( Q \) would be:
- The x-coordinate of \( Q \) would be \( x_P + 15 = -4 + 15 = 11 \).
- The y-coordinate of \( Q \) would be \( y_P + 8 = 7 + 8 = 15 \).
Thus, another possible coordinate for \( Q \) is \( (11, 15) \).
Summary of Integer Coordinates
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Using the shorter leg horizontally:
- \( Q = (4, 22) \)
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Using the shorter leg vertically:
- \( Q = (11, 15) \)
Both coordinate pairs satisfy the condition that the x- and y-coordinates of \( Q \) are greater than those of \( P \) (i.e., both \( 4 > -4 \) and \( 22 > 7 \) for the first pair, and \( 11 > -4 \) and \( 15 > 7 \) for the second pair).