The volume \( V \) of a pyramid can be calculated using the formula:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
For a pyramid with a square base, the base area \( A \) can be calculated as:
\[ A = \text{side length}^2 \]
In this case, the side length of the base is 141 m. Therefore, the base area is:
\[ A = 141 , \text{m} \times 141 , \text{m} = 19881 , \text{m}^2 \]
Now, using the height of the pyramid, which is 90 m, we can find the volume:
\[ V = \frac{1}{3} \times 19881 , \text{m}^2 \times 90 , \text{m} \]
Calculating the volume:
\[ V = \frac{1}{3} \times 19881 \times 90 \]
\[ V = \frac{1}{3} \times 1788290 \]
\[ V = 596096.67 , \text{m}^3 \]
Therefore, the volume of the pyramid is approximately \( 596096.67 , \text{m}^3 \) or \( 596097 , \text{m}^3 \) when rounded to the nearest whole number.
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