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Part 1
In a certain Algebra and Trigonometry​ class, there are 6 male​ freshmen, 13 female​ freshmen, 6 male​ sophomores, and 3 female sophomores. If a person is selected randomly from the​ group, find the probability that the selected person is a freshman or female.

1 answer

To find the probability that a randomly selected person from the group is either a freshman or female, we need to count the total number of males and females in the class, as well as how many of those are freshmen.

Step 1: Determine total number of students

We can break the counts down as follows:

  • Male Freshmen: 6
  • Female Freshmen: 13
  • Male Sophomores: 6
  • Female Sophomores: 3

Total calculation:

  • Total number of students = Male Freshmen + Female Freshmen + Male Sophomores + Female Sophomores
  • Total number of students = 6 + 13 + 6 + 3 = 28

Step 2: Count the favorable outcomes

Next, we need to find the number of students who are either freshmen or female.

Counting freshmen:

  • Total Freshmen = Male Freshmen + Female Freshmen = 6 + 13 = 19

Counting females:

  • Total Females = Female Freshmen + Female Sophomores = 13 + 3 = 16

Step 3: Apply the principle of inclusion-exclusion

Some students are counted in both freshmen and females, specifically the female freshmen. We must be careful not to double-count them.

Female Freshmen:

  • Female Freshmen = 13

Using the principle of inclusion-exclusion: P(FreshmanFemale)=P(Freshman)+P(Female)P(FreshmanFemale)

Calculating those probabilities:

  • Number of freshmen = 19
  • Number of females = 16
  • Number of female freshmen = 13

Step 4: Calculate the total number of favorable outcomes:

Total number of favorable outcomes: 19+1613=22

Step 5: Calculate the probability

Now, we can calculate the probability: P(FreshmanFemale)=Number of favorable outcomesTotal number of students P(FreshmanFemale)=2228=1114

Final Result

So the probability that a randomly selected person is either a freshman or female is: 1114