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Part 1
An urn contains balls numbered 1 through 10. A ball is​ chosen, returned to the​ urn, and a second ball is chosen. What is the probability that the first and second balls will be a 6​?

1 answer

To find the probability of drawing a ball numbered 6 on both the first and second draws from an urn containing balls numbered 1 through 10, we follow these steps:

  1. Identify the Total Number of Outcomes: Since there are 10 balls, there are 10 possible outcomes for each draw.

  2. Determine the Probability of Drawing a 6:

    • The probability of drawing a ball numbered 6 in one draw is \( P(6) = \frac{1}{10} \).
  3. Calculate the Probability for Two Independent Draws:

    • Since the ball is returned to the urn after the first draw, the two draws are independent. Thus, the probability of both draws resulting in a 6 is the product of the probabilities of each individual draw: \[ P(\text{6 on 1st and 6 on 2nd}) = P(6) \times P(6) = \frac{1}{10} \times \frac{1}{10} = \frac{1}{100}. \]

Therefore, the probability that both the first and second balls will be a 6 is \(\frac{1}{100}\) or 0.01.