To determine the probability of drawing a card that has a value of 6 and is also a face card from a standard deck of 52 cards, we need to understand the definitions of “value of 6” and “face card”.
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Cards with a value of 6: In a standard deck, there are four cards with the value of 6 (6 of Hearts, 6 of Diamonds, 6 of Clubs, and 6 of Spades).
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Face cards: The face cards in a standard deck are the Kings, Queens, and Jacks. There are three face cards in each of the four suits, so there are a total of 12 face cards (3 face cards × 4 suits).
Now we analyze the question:
- A card cannot simultaneously be a value of 6 and a face card. A value of 6 is simply a numbered card and does not fall under face cards, which are specifically Kings, Queens, and Jacks.
Since there are no cards that meet both criteria at the same time (being a value of 6 and also being a face card), the number of favorable outcomes is 0.
To find the probability, we use the formula:
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
Substituting the values we have:
\[ \text{Probability} = \frac{0}{52} = 0 \]
Thus, the probability that the card will have a value of 6 and be a face card is 0.