To determine which of the given pairs \((x, y)\) (where \(x\) is the number of chemistry sets and \(y\) is the number of robotics kits) is a viable solution, we need to set up the equation based on Cindy's budget:
The total cost of the chemistry sets and robotics kits must equal her winnings:
\[ 8x + 10y = 50 \]
Now, let's check each of the provided options:
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\((-5, 9)\): \[ 8(-5) + 10(9) = -40 + 90 = 50 \quad \text{(Valid equation, but cannot buy negative chemistry sets)} \] This is not viable.
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\((5, 1)\): \[ 8(5) + 10(1) = 40 + 10 = 50 \quad \text{(Valid solution)} \] This is viable.
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\((0, 5)\): \[ 8(0) + 10(5) = 0 + 50 = 50 \quad \text{(Valid solution)} \] This is also viable.
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\((3, 2.6)\): \[ 8(3) + 10(2.6) = 24 + 26 = 50 \quad \text{(Valid equation, but cannot buy partial kits)} \] This is not viable.
Thus, the viable solutions from the options given are \((5, 1)\) and \((0, 5)\).