I would use percentage of calcium in CaCl2.2H2O
Percent= molmassCa/131.015
muliply that by 2.55..
Question: "Calculate the theoretical yield of calcium carbonate of you react 2.55g of calcium chloride dihydrate with an excess amount of sodium carbonate."
I got the molar mass of calcium chloride dihydrate which is 131.015 g/mol, but Im not sure how to start the equation for the theoretical yield...
2.55g X ?????
2 answers
you would use Calcium because its the limiting reactant?
So... 40.078/131.015 = .305903
Then... 2.55g X .305903g Ca/1g = the theoretical yield?
So... 40.078/131.015 = .305903
Then... 2.55g X .305903g Ca/1g = the theoretical yield?