Let's address each of the questions step by step based on the information provided regarding the big-footed/small-footed turtle cross.
Question 18
What percent of the F1 generation were short? In the cross of a heterozygous big-footed turtle (Bb) with a small-footed turtle (bb), the resulting offspring phenotypes will be 50% big-footed (Bb) and 50% small-footed (bb).
Answer: 50%
Question 19
Fill in the blanks that correspond with the missing information in the Punnett square.
When we cross Bb (top row) with bb (left column), we get:
- 1st Row: Bb, Bb
- 2nd Row: bb, bb
The filled blanks according to this would be:
- B
- b
- B
- b
- Bb
- bb
- Bb
- bb
Question 20
What is the ratio of possible phenotypes of the F1 generation?
From the Punnett square:
- 2 big-footed (Bb)
- 2 small-footed (bb)
The ratio of big-footed to small-footed is 2:2, which simplifies to 1:1.
Answer: 1 big-footed : 1 small-footed
Question 21
What is the ratio of possible genotypes of the F1 generation?
Again from the Punnett square:
- 2 Bb (heterozygous big-footed)
- 2 bb (homozygous small-footed)
The ratios of genotypes would be:
- 2 Bb: 2 bb This simplifies to 1 Bb : 1 bb.
Answer: 1 : 1
Question 22
What is the genotype in the lower right hand quadrant?
The lower right-hand quadrant of the Punnett square corresponds to the combination of b (from the small-footed turtle) with b (from the small-footed turtle), which results in:
Answer: bb
Question 23
What is the probability that their next offspring will have big feet?
The offspring's genotypes will be:
- 2 Bb (big-footed)
- 2 bb (small-footed)
Thus, the probability of having big feet (Bb) is 2 out of 4, which simplifies to 1/2.
Answer: 1/2
1 answer