Question: Antimony (V) chloride, SbCl5, dissociates on heating to SbCl5(g)goes to SbCl3(g)+ Cl2(g). A closed 3.50 L vessel initially contains 0.0125 mol SbCl5. what is the total pressure at 248 degree's C when equilibrium is achieved? The value of Kc at 248 degree C is 2.50E-2.
How would you go about solving this problem? Would you do an ICE table? How would you find total pressure?
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I think I would convert 0.0125 moles SbCl5 in 3.5 L to concn, then do an ICE table, and calculate concns of each specie. Convert M of each to moles, add moles to get total moles, then PV = nRT. I think that will do it. Check my thinking.
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