Question

Question

A young snake eats and digests a mouse. The increase in the snake’s mass equals(1 point)
Responses

the mass of the mouse plus the original mass of the snake.
the mass of the mouse plus the original mass of the snake.

the mass of the mouse plus the mass of waste produced by the snake.
the mass of the mouse plus the mass of waste produced by the snake.

only the mass of the mouse
only the mass of the mouse

the mass of the mouse minus the mass of waste produced by the snake.

Answer 1

The correct response is:

the mass of the mouse minus the mass of waste produced by the snake.

This is because when the snake eats a mouse, it gains mass from the mouse, but also loses some mass through waste that it produces during digestion. Therefore, the net increase in the snake's mass will be the mass of the mouse minus the mass of the waste.

Answer 2

Cellular respiration transforms glucose and oxygen into carbon dioxide, water, and energy.



C6H12O6 + 6O2 → 6CO2 + ?H2O + Energy



Based on the law of conservation of matter, what is the missing coefficient for water?

(1 point)
Responses

8
8

2
2

4
4

6
6

Answer 3

To determine the missing coefficient for water in the equation of cellular respiration, let's balance the equation step by step.

The general equation for cellular respiration is:

\[ \text{C}6\text{H}{12}\text{O}_6 + 6\text{O}_2 \rightarrow 6\text{CO}_2 + ?\text{H}_2\text{O} + \text{Energy} \]

Balancing the equation:

1. Carbons:

   • In one molecule of glucose (C₆H₁₂O₆), there are 6 carbon atoms.
   • Thus, to balance carbons, we produce 6 CO₂. (Balanced)

2. Oxygens:

   • In glucose, there are 6 oxygen atoms.
   • Each molecule of glucose also reacts with 6 O₂, providing 12 oxygen atoms (6 from glucose and 6 from O₂).
   • On the product side, we have 6 CO₂, which contributes 12 oxygen atoms (6 × 2 = 12) and ?H₂O which contributes oxygen as well.

   So we have:

   • 12 O (from CO₂) + ? O (from H₂O) = 12 O (from glucose and O₂)
   • Since we are starting with 12 O in total (6 from glucose and 6 from 6 O₂), we can simplify the situation.

Given that we are using O₂ to create CO₂ and H₂O:

• Each H₂O contributes 1 oxygen.
• Since we already have 12 from CO₂, we have the following contribution:
• 6 from each CO₂ (6 molecules) + X from H₂O = 12 total O.

For every two molecules of water produced, we need two oxygen atoms, hence:

Let’s count up to the total, substituting different values for H₂O to find the missing coefficient.

Through trial:

If we set ? = 6:

6 CO₂ contributes 12 O, 6 H₂O contributes another 6 O.

Total = 12 + 6 = 18.

This output exceeds the initial amount, meaning this is not accurate.

Instead if we assume ? = 6, we effectively have 6H₂O producing, reducing the original O use.

After several iterations, we find that the total must be 6H₂O.

So the answer is:

6