To find the width of the park, we can use the formula for the area of a rectangle, which is:
\[ \text{Area} = \text{Length} \times \text{Width} \]
We can rearrange this to solve for the width:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} \]
We are given:
- Area = \(1.36 \times 10^8 , \text{ft}^2\)
- Length = \(1.6 \times 10^4 , \text{ft}\)
Now substituting in the values:
\[ \text{Width} = \frac{1.36 \times 10^8}{1.6 \times 10^4} \]
We can divide the coefficients (1.36 and 1.6) and subtract the exponents of 10:
\[ \text{Width} = \frac{1.36}{1.6} \times 10^{8 - 4} \]
Calculating the coefficient:
\[ \frac{1.36}{1.6} = 0.85 \]
Now applying the exponent:
\[ \text{Width} = 0.85 \times 10^{4} \]
To express \(0.85\) in scientific notation:
\[ 0.85 = 8.5 \times 10^{-1} \]
So, we substitute:
\[ \text{Width} = 8.5 \times 10^{-1} \times 10^{4} = 8.5 \times 10^{3} \]
Therefore, the width of the park is:
\[ \text{Width} = 8.5 \times 10^{3} , \text{ft} \]
Thus, the correct response is:
8.5×103 ft.