The proportion that could be used to find the distance in feet a cockroach can travel in ½ minute is:
44 feet / 10 seconds = f feet / 30 seconds
This can be simplified to:
44 / 10 = f / 30
4.4 = f / 30
f = 4.4 * 30
f = 132 feet
Therefore, a cockroach can travel 132 feet in ½ minute.
Question
A cockroach can travel at a speed of 3 mph, which is equivalent to 44 feet every 10 seconds. Which proportion could be used to find f, the distance in feet a cockroach can travel in ½ minute?
1 answer
1 answer