The equation for the height of the ball in feet after t seconds is h(t) = -16t^2 + 46t.
To find when the ball hits the ground, we need to find when h(t) = 0. Therefore, we set -16t^2 + 46t = 0.
-16t^2 + 46t = 0
-2t(8t - 23) = 0
t = 0 or t = 23/8
Since time cannot be negative, the ball will hit the ground after approximately 2.875 seconds.
Therefore, the correct answer is 3.
Question A ball is thrown into the air with an initial upward velocity of%C2%A046 ft/s. Its height (h) in feet after t seconds is given by the function . After how many seconds will the ball hit the ground?%C2%A0 (1 point) Responses 3 3 4 4 5 5 6
1 answer
1 answer