To determine which point among the options represents a viable solution for the weight of apples (x) and oranges (y), we need to consider the constraints given in the scenario:
-
The total weight of apples and oranges cannot exceed 15 pounds: \[ x + y \leq 15 \]
-
The weight of the apples cannot exceed 6 pounds: \[ x \leq 6 \]
Now, let's evaluate each of the points provided:
A. (2, 12)
- \(x + y = 2 + 12 = 14 \leq 15\) (satisfied)
- \(x = 2 \leq 6\) (satisfied)
- Viable solution
B. (8, 9)
- \(x + y = 8 + 9 = 17\) (not satisfied)
- Not a viable solution
C. (12, 4)
- \(x + y = 12 + 4 = 16\) (not satisfied)
- Not a viable solution
D. (6, -2)
- \(x + y = 6 + (-2) = 4 \leq 15\) (satisfied)
- \(x = 6 \leq 6\) (satisfied)
- However, weight cannot be negative (y = -2 is not realistic).
- Not a viable solution
Based on this analysis, the only point that meets all the criteria without any issues is A. (2, 12).