Question 6

During his vacation, Dalyn rents a small boat from a rental service that charges a flat fee of $30 plus $10 per hour (including taxes). The total charge comes to $90. Which equation can be used to calculate the number of hours, x, that Dalyn rents the boat?
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1 point
A. 10x + 30 = 90; 6 hours
B. 10(x + 30) = 90; 5 hours
C. 30x + 10 = 90; 6 hours
D. 30 (x + 10) = 90; 5 hours
Question 7
Lamont has purchased 20 trading cards and wants to have at least 50 trading cards. Write and solve an inequality to find the number of trading cards Lamont needs. Select all of the true statements.
*
1 point
A. x + 20 ≥ 50
B. x + 20 ≤ 50
C. x ≥ 30
D. x ≤ 30
E. x ≥ 70

1 answer

Question 6:

To find the equation that can be used to calculate the number of hours, \( x \), that Dalyn rents the boat, you need to consider the rental cost structure. The total charge is made up of a flat fee of $30 plus $10 for each hour rented.

The total charge is represented as:

\[ \text{Total charge} = \text{Flat fee} + \text{Hourly rate} \times \text{Hours} \]

So, we can write it as:

\[ 30 + 10x = 90 \]

Now, to see which option matches this equation:

A. \( 10x + 30 = 90 \) → This is correct.

B. \( 10(x + 30) = 90 \) → This is incorrect.

C. \( 30x + 10 = 90 \) → This is incorrect.

D. \( 30(x + 10) = 90 \) → This is incorrect.

The correct choice is:

A. 10x + 30 = 90; 6 hours

To find the number of hours, we can solve the equation:

\[ 10x + 30 = 90 \] \[ 10x = 90 - 30 \] \[ 10x = 60 \] \[ x = 6 \]


Question 7:

Lamont wants to have at least 50 trading cards and currently has 20. Let \( x \) represent the number of additional trading cards needed. The inequality can be formulated as:

\[ x + 20 \geq 50 \]

Now, let's solve this inequality:

\[ x + 20 \geq 50 \] \[ x \geq 50 - 20 \] \[ x \geq 30 \]

Now, let's examine the provided options:

A. \( x + 20 \geq 50 \) → True statement (this is the inequality we derived).

B. \( x + 20 \leq 50 \) → False statement.

C. \( x \geq 30 \) → True statement (this is what we derived).

D. \( x \leq 30 \) → False statement.

E. \( x \geq 70 \) → False statement.

True statements are:

A. \( x + 20 \geq 50 \) and C. \( x \geq 30 \).