To find the perimeter of a rectangle, the formula is given by:
\[ \text{Perimeter} = 2 \times (\text{length} + \text{width}) \]
In this case, the length is \(b\) yards and the width is \(a\) yards, where \(a = \frac{1}{3}b\).
We can express the perimeter \(P\) in two different ways:
- Using \(a\) and \(b\):
\[ P = 2 \times (a + b) \]
Substituting \(a\) with \(\frac{1}{3}b\):
\[ P = 2 \times \left(\frac{1}{3}b + b\right) \] \[ P = 2 \times \left(\frac{1}{3}b + \frac{3}{3}b\right) \] \[ P = 2 \times \left(\frac{4}{3}b\right) \] \[ P = \frac{8}{3}b \]
So, the first expression for the perimeter is:
\[ P = \frac{8}{3}b \]
- Using only \(b\) and substituting \(a\):
Another way to express the perimeter directly in terms of \(b\):
Since \(a = \frac{1}{3}b\), we can still write the perimeter using the initial formula:
\[ P = 2 \times (b + a) \]
Replacing \(a\):
\[ P = 2 \times \left(b + \frac{1}{3}b\right) \] \[ P = 2 \times \left(\frac{3}{3}b + \frac{1}{3}b\right) \] \[ P = 2 \times \left(\frac{4}{3}b\right) \] \[ P = \frac{8}{3}b \]
Thus, both expressions you can use for the perimeter of A’Leila's pen are:
- \(P = \frac{8}{3}b\)
- \(P = 2(a + b)\) (where \(a = \frac{1}{3}b\))