Here are the answers for your questions:
Question 3:
What do the squares in a pedigree represent?
c Males in a family.
Question 4:
For sneaky snakes, being rude (R) is dominant to being respectful (r). Complete the cross below, and determine the phenotype (dominant : recessive) ratio.
| | R | r | |---|---|---| | r | Rr (1) | rr (2) | | r | Rr (3) | rr (4) |
The offspring are Rr (rude) and rr (respectful). Each row corresponds to the offspring produced:
- Rr => Rude
- rr => Respectful
- Rr => Rude
- rr => Respectful
So the phenotype ratio is: 2 (rude) : 2 (respectful)
Thus, Blank 5 = 2 and Blank 6 = 2.
Column A:
- #1: a. Rr
- #2: b. rude
- #3: a. Rr
- #4: e. rr
- #5: b. rude
- #6: d. respectful
Question 5:
A male cat that is homozygous dominant for the A trait (AA) is mated with a female cat that is homozygous recessive (aa). The offspring (all Aa) will be heterozygous. The probability of getting a heterozygous offspring is:
- From the cross:
- Aa (4 offspring)
- So, the probability is 4 out of 4 or simplifies to 1 out of 1.
Blank 1: 1
Blank 2: 1
Question 6:
To determine the percentage of pink flowered offspring in the F2 generation of two pink flowering fruitloop plants (WR x WR):
| | W | R | |---|---|---| | W | WW (25%) | WR (50%) | | R | WR (50%) | RR (25%) |
In this case:
- WW (white) = 25%
- WR (pink) = 50%
- RR (red) = 25%
The total percentage for pink (WR) are from 2 squares:
50% pink (from WRs two entries) + 0% (from WW and RR)
So in total, Pink = 50%.
The answer is c. 50% pink.
Question 7:
In the cross of a homozygous white-eyed female (XrXr) with a red-eyed male (XRY), the possible genotypes will be:
- Female offspring: XrX (all will have white eyes).
- Male offspring: XRY (all will have red eyes).
Hence, the right answer is: b. 100% of the females with red eyes, 100% of the males with white eyes.
Question 8:
For a dihybrid cross, the expected genotype in the bottom right-hand corner (red square):
- The possible genotypes depend on the specific plants being crossed. A dihybrid cross results in a 9:3:3:1 ratio.
- If we assume BbGg is the cross, which gives us 1/16 GGbb.
Blank 1: ggbb.
Question 9:
For clouded leopards, since one cub has normal spots (indicating at least one XN), and the other has dark spots (indicating it has the genotype for dark spots), we can determine the mother's genotype:
- The mother could be either homozygous (XN XN) or heterozygous (XN Xn).
However, since there are cubs with dark spots (Xn Y), we can confirm that the mother must be at least heterozygous. Thus, c. heterozygous is the correct answer.
Question 10:
Disadvantages to sexual reproduction include:
- a. slower reproduction rate
- b. less reliable reproduction
- f. takes time and energy to find mate
Correct answers are a, b, and f.
I hope this helps with your understanding of these genetic concepts!