Let's address each question one by one based on the information provided.
Question 3
We need to analyze the rational function given: \[ f(x) = \frac{x + 4}{x^2 - 16} \]
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Vertical Asymptotes: These occur where the denominator equals zero (and the numerator is not zero at those points).
- The denominator \( x^2 - 16 = 0 \) gives: \[ x^2 = 16 \implies x = \pm 4 \]
- This means vertical asymptotes at \( x = 4 \) and \( x = -4 \).
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Horizontal Asymptotes: For rational functions, we observe the degrees of the numerator and denominator:
- Degree of numerator (1) < degree of denominator (2). Thus, the horizontal asymptote is at \( y = 0 \).
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Point of Discontinuity: This occurs where the function is undefined, which is at \( x = 4 \) and \( x = -4 \).
So, the correct choice is:
- Vertical asymptote: \( x = 4 \)
- Horizontal asymptote: \( y = 0 \)
- Point of discontinuity: when \( x = -4 \)
Question 4
Given the function: \[ C = \frac{320}{x} + 15 \] We analyze the behavior associated with adding water in the mixture.
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Increasing or Decreasing: The function represents the concentration of fertilizer as you add more water. As you add more water (increasing \( x \)), the concentration \( C \) decreases (since \( C \) is dependent on \( \frac{320}{x} \)), approaching 0% but never reaching it since you are adding more water to the same amount of fertilizer.
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Horizontal Asymptote: As the amount of water increases indefinitely, the fraction \( \frac{320}{x} \) approaches 0, leading to a concentration around 15%, but since we are adding more water, we observe that the concentration goes to less than 15%.
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Domain: \( x \) cannot be negative because we cannot add negative ounces of water.
Therefore, the correct choice is:
- The function is a decreasing function, so as the number of ounces of water added to the mixture increases, the concentration of fertilizer decreases but not at a constant rate.
Question 5
Given the function: \[ C = \frac{500 + 0.5x}{x - 50} \]
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Horizontal Asymptote: To find the behavior as \( x \) becomes very large:
- The leading coefficient of the numerator is \( 0.5 \) and for the denominator, it's 1. Therefore, the horizontal asymptote is at \( y = 0.5 \) as \( x \to \infty \).
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Increasing or Decreasing: As \( x \) increases, mainly after reaching the startup cost, the average cost per widget initially decreases and then stabilizes as production increases, due to the fixed cost being spread over an increasing number of items.
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Range: The range of \( C \) does not contain negative values since average cost cannot be negative.
Thus, the correct choice is:
- The function has a horizontal asymptote at \( C = 0.5 \), so as the number of widgets produced increases, the average cost per widget produced approaches $0.50.
If you have any further questions or need additional explanations, feel free to ask!