Question 28

Question

Match the missing coefficient to the correct number of molecules so that the equation adheres to the conservation of mass.

(X)N2 + (Y)H2 → (Z)NH3

Column A
1.
X:
X
2.
Y:
Y
3.
Z:
Z
Column B
a.2
b.1
c.3

Answer 1

To balance the chemical equation \(N_2 + H_2 \rightarrow NH_3\), we need to make sure the number of each type of atom is the same on both sides of the equation.

1. Nitrogen (N): On the left, we have 2 nitrogen atoms from \(N_2\). On the right, each \(NH_3\) contains 1 nitrogen atom. Therefore, we need 2 \(NH_3\) to balance the nitrogen.

2. Hydrogen (H): Each \(NH_3\) contains 3 hydrogen atoms. If we have 2 \(NH_3\), that gives us \(2 \times 3 = 6\) hydrogen atoms on the right side. To get 6 hydrogen atoms from \(H_2\) on the left, we need 3 \(H_2\) molecules because each \(H_2\) contains 2 hydrogen atoms.

This gives us:

• X (for \(N_2\)): 1
• Y (for \(H_2\)): 3
• Z (for \(NH_3\)): 2

Now matching these coefficients to Column A and Column B:

• X: 1 (which corresponds to \(b.1\))
• Y: 3 (which corresponds to \(a.2\))
• Z: 2 (which corresponds to \(c.3\))

Final answers:

• X → b.1
• Y → a.2
• Z → c.3