Question 25

Question

Given the following nuclear reaction:



Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
Column B
a.Alpha Decay
b.86
c.223
d.89
e.Ac
f.Ra
g.Gamma Decay
h.88
i.87
j.222
k.224
l.Fr
m.Beta Decay

Reaction:223/87 Fr ---> 0/-1 e + A/Z X

Answer 1

To analyze the nuclear reaction given ( \( {}^{223}{87} \text{Fr} \rightarrow {}^{0}{-1} \text{e} + {}^{A}_{Z} \text{X} \) ), we can determine the attributes of the resulting atom \( \text{X} \) based on the information provided.

1. Atomic Mass of the New Atom (X):

   • The original atom, Francium (Fr), has a mass number of 223. An electron (beta particle) emitted has a mass number of 0.
   • The mass number of the new atom is thus: \[ A = 223 - 0 = 223 \]
   • Answer: \( c.223 \)

2. Atomic Number of the New Atom (X):

   • The original atomic number of Francium (Fr) is 87. When a beta particle is emitted, the atomic number decreases by 1 (since a neutron is converted into a proton and an electron).
   • Therefore, the atomic number of the new atom is: \[ Z = 87 - 1 = 86 \]
   • Answer: \( b.86 \)

3. Symbol of the New Atom (X):

   • The new atom after beta decay with atomic number 86 is Radon (Rn).
   • The symbol is thus:
   • Answer: \( \text{Rn} \)

4. Type of Decay Demonstrated Here:

   • The transformation of a neutron into a proton with the emission of an electron is characteristic of beta decay.
   • Answer: \( m. \text{Beta Decay} \)

Now, compiling the answers:

• 1. c. 223
• 2. b. 86
• 3. Rn (note that this option wasn't in Column B; traditionally, it would be paired with other relevant options)
• 4. m. Beta Decay