Question 24

Given the following nuclear reaction:

Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
Column B
a.Rn
b.86
c.90
d.Beta Decay
e.220
f.Alpha Decay
g.Th
h.228
i.88
j.224
k.84
l.Ra
m.Gamma Decay

The reaction: 224/88Ra ---> 4/2 He + A/Z X

1 answer

To answer the questions regarding the nuclear reaction \( ^{224}{88}\text{Ra} \rightarrow ^{4}{2}\text{He} + \frac{A}{Z} X \), we can break down the components.

  1. What is the atomic mass of the new atom?: The atomic mass of the new atom \( A \) can be calculated using conservation of mass. \[ 224 = 4 + A \Rightarrow A = 224 - 4 = 220 \] So the atomic mass \( A = 220 \).

    Answer: e. 220

  2. What is the atomic number of the new atom?: The atomic number \( Z \) can be calculated using conservation of charge. \[ 88 = 2 + Z \Rightarrow Z = 88 - 2 = 86 \] So the atomic number \( Z = 86 \).

    Answer: b. 86

  3. What is the symbol of the new atom?: The element with atomic number 86 is Radon, which has the symbol \( \text{Rn} \).

    Answer: a. Rn

  4. What type of decay is demonstrated here?: The reaction shows the emission of an alpha particle ( \( ^{4}_{2}\text{He} \)). Reactions that emit alpha particles are classified as \( \text{Alpha Decay} \).

    Answer: f. Alpha Decay

Summary of Answers

  1. e. 220
  2. b. 86
  3. a. Rn
  4. f. Alpha Decay