Question 2 of 10
How many real number solutions are there to the equation 0 = –3x² + x – 4?
A. 0
B. 1
C. 2
D. 3
3 answers
C. 2
C is wrong, since the discriminant is negative.
Looks like A to me.
Looks like A to me.
You are correct. The discriminant of the quadratic equation is:
b² - 4ac = 1 - 4(-3)(-4) = 49
Since the discriminant is positive, there are real number solutions. However, there are no solutions that satisfy the equation because the quadratic equation has no real roots. Therefore, the answer is A. 0.
b² - 4ac = 1 - 4(-3)(-4) = 49
Since the discriminant is positive, there are real number solutions. However, there are no solutions that satisfy the equation because the quadratic equation has no real roots. Therefore, the answer is A. 0.
1 answer