Question 2

Question

A)Given the equation 8(n+6)=104, identify the real-world problem that corresponds to this equation.(1 point)
Responses

Image with alt text: A rectangle is divided into two sections. One section has a length of 8 and a width of n comprised of a 2 by 4 matrix of square boxes. The second section has a width of n plus 6 and length of 8 comprised of a 3 by 4 matrix of square boxes. Above the rectangle it reads: upper A equals 104 square units.

Image with alt text: A rectangle of is divided into two sections. One section has a length of n and a width of 6 comprised of a 2 by 4 matrix of square boxes. The second section has a length of 8 and a width of 6 comprised of a 3 by 4 matrix of square boxes. Above the rectangle it reads: upper A equals 104 square units.

Image with alt text: A rectangle is divided into two sections. One section has a length of 8 and width of 6 comprised of a 2 by 4 matrix of square boxes. The second section has a length of 8 and width of n c

Answer 1

The equation \(8(n + 6) = 104\) corresponds to a real-world problem involving the area of a rectangle.

In this scenario, you can interpret the components of the equation as follows:

• The expression \(n + 6\) represents the width of one section of the rectangle, where \(n\) is a variable whose value we need to determine.
• The number \(8\) indicates the length of the rectangle.
• The area of this rectangle, represented by the product of its length and width, equals \(104\) square units, which is the area given in the problem.

Thus, the problem can be described as follows:

A rectangle is divided into two sections. The first section has a fixed length of \(8\) units and a variable width of \(n + 6\) units. The total area of the rectangle composed of these two sections is \(104\) square units. The equation \(8(n + 6) = 104\) can be used to find the unknown width \(n\).