Question 1Solve the inequality for x. 2/3x + 3 < 9

Answer 1

To solve the inequality \( \frac{2}{3}x + 3 < 9 \), follow these steps:

1. Subtract 3 from both sides: \[ \frac{2}{3}x < 9 - 3 \] \[ \frac{2}{3}x < 6 \]

2. Multiply both sides by \(\frac{3}{2}\) to isolate \(x\). Remember, since \(\frac{3}{2}\) is positive, the direction of the inequality does not change: \[ x < 6 \times \frac{3}{2} \] \[ x < 9 \]

Thus, the solution to the inequality is: \[ x < 9 \]