First, we need to determine the amount of NH3 produced when 6.30 grams of H2 reacts completely.
1. Calculate the number of moles of H2:
6.30 grams H2 * (1 mol / 2.0 grams) = 3.15 mol H2
2. Use the mole ratio from the balanced chemical equation to determine the moles of NH3 produced:
3.15 mol H2 * (2 mol NH3 / 3 mol H2) = 2.10 mol NH3
3. Calculate the mass of NH3 produced:
2.10 mol NH3 * 17.0 grams/mol = 35.7 grams of NH3
Therefore, the answer is a) 35.7 grams of NH3.
Question 18 (2 points)
In the equation below, Nitrogen gas (N2) and Hydrogen gas (H2) react to produce Ammonia (NH3).
N2(g)+3H2(g)--->2NH3(g)
If 6.30 grams of Hydrogen reacts completely with nitrogen, how many grams of ammonia will be produced?
The molar mass of Hydrogen gas (H2)is 2.0 grams/mol.
The molar mass of Ammonia (NH3) is 17.0 grams/mol.
If you are unsure how to convert from grams to grams, please see the example problem linked HERE.
a
35.7 grams of NH3
b
38.5 grams of NH3
c
143 grams of NH3
d
80.3 grams of NH3
1 answer
1 answer