Question 16

Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)

(1 point)
Responses

10−30h=0
10 minus 30 h is equal to 0

1280+30h=0
1280 plus 30 h is equal to 0

1280−30h=0
1280 minus 30 h is equal to 0

30h=10

Answer 1

To determine how long the water in the cooler will last, we can set up the equation based on the information provided:

1. The total amount of water in the cooler is 1,280 ounces (since 10 gallons = 1,280 ounces).
2. Each hour, 30 ounces of water are removed.

Let \( h \) represent the number of hours the water lasts. The equation representing the situation can be set up as follows:

\[ 1280 - 30h = 0 \]

This means that after \( h \) hours of drinking 30 ounces of water each hour, the total amount of water left in the cooler will be 0 ounces.

So, the correct response is:

1280 − 30h = 0
1280 minus 30 h is equal to 0.