Question 13 (2 points)

According to Kepler's 3rd Law, Where orbital period is determined by distance from the Sun, Match the planet with it's orbital period.

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Column A
1.
Earth:
Earth
2.
Neptune:
Neptune
3.
Mercury:
Mercury
4.
Saturn:
Saturn
Column B
a.60,190 days
b.88 days
c.10,759 days
d.365 days

1 answer

To match the planets with their orbital periods based on Kepler's 3rd Law, we can use the standard orbital periods:

  • Earth: 365 days
  • Neptune: 60,190 days
  • Mercury: 88 days
  • Saturn: 10,759 days

Now, let's match them:

Column A | Column B
--- | ---

  1. Earth: | d. 365 days
  2. Neptune: | a. 60,190 days
  3. Mercury: | b. 88 days
  4. Saturn: | c. 10,759 days

So the matches are:

  1. Earth: d. 365 days
  2. Neptune: a. 60,190 days
  3. Mercury: b. 88 days
  4. Saturn: c. 10,759 days