Question 12 options:
Find the square root of this number.
square root of 36 end root
35 answers
6
Solve the problem.
Six times Tim's age is 54. His sister's age times three is also 54. How old are Tim and his sister Amy?
Six times Tim's age is 54. His sister's age times three is also 54. How old are Tim and his sister Amy?
Let's assign variables to represent Tim's age (T) and Amy's age (A). We can set up two equations based on the given information:
1) Six times Tim's age is 54: 6T = 54
2) Amy's age times three is 54: 3A = 54
To solve these equations, we can divide both sides of equation 1) by 6 and both sides of equation 2) by 3:
1) T = 9
2) A = 18
Therefore, Tim is 9 years old and his sister Amy is 18 years old.
1) Six times Tim's age is 54: 6T = 54
2) Amy's age times three is 54: 3A = 54
To solve these equations, we can divide both sides of equation 1) by 6 and both sides of equation 2) by 3:
1) T = 9
2) A = 18
Therefore, Tim is 9 years old and his sister Amy is 18 years old.
Solve the problem.
Sections A - F of the football stadium each have 144 seats. There are as many rows as there are seats in each row. Without dividing, how many seats were in each row?
Select the correct answer.
Question 14 options:
13 seats
12 seats
7 seats
Sections A - F of the football stadium each have 144 seats. There are as many rows as there are seats in each row. Without dividing, how many seats were in each row?
Select the correct answer.
Question 14 options:
13 seats
12 seats
7 seats
To determine the number of seats in each row, we need to find the square root of the total number of seats in each section.
Since each section has 144 seats, we can find the square root of 144 to determine how many seats are in each row.
The square root of 144 is 12.
Therefore, there are 12 seats in each row.
The correct answer is: 12 seats.
Since each section has 144 seats, we can find the square root of 144 to determine how many seats are in each row.
The square root of 144 is 12.
Therefore, there are 12 seats in each row.
The correct answer is: 12 seats.
Question 15 options:
Solve the problem.
Sandwiches sell for $3.50 at Blake's shop. Soft drinks sell for $1.00 each. If Blake served 75 people during lunch rush, and each bought a sandwich and a soft drink, how much money did Blake earn?
Solve the problem.
Sandwiches sell for $3.50 at Blake's shop. Soft drinks sell for $1.00 each. If Blake served 75 people during lunch rush, and each bought a sandwich and a soft drink, how much money did Blake earn?
Let's calculate the total amount of money Blake earned by selling sandwiches and soft drinks during the lunch rush.
The price of each sandwich is $3.50, and we know that 75 people bought sandwiches. So, the total amount of money earned from sandwich sales is 75 x $3.50 = $262.50.
The price of each soft drink is $1.00, and since each person also bought a soft drink, the total amount of money earned from soft drink sales is also 75 x $1.00 = $75.00.
To find the total amount of money earned, we can add the earnings from sandwich sales and soft drink sales together: $262.50 + $75.00 = $337.50.
Therefore, Blake earned $337.50 during the lunch rush.
The price of each sandwich is $3.50, and we know that 75 people bought sandwiches. So, the total amount of money earned from sandwich sales is 75 x $3.50 = $262.50.
The price of each soft drink is $1.00, and since each person also bought a soft drink, the total amount of money earned from soft drink sales is also 75 x $1.00 = $75.00.
To find the total amount of money earned, we can add the earnings from sandwich sales and soft drink sales together: $262.50 + $75.00 = $337.50.
Therefore, Blake earned $337.50 during the lunch rush.
Question 16 options:
Find the equivalent fraction
16 over 20 space equals space 4 over _
Find the equivalent fraction
16 over 20 space equals space 4 over _
To find the equivalent fraction to 16/20, we can simplify it by dividing both the numerator and denominator by their greatest common factor.
The greatest common factor of 16 and 20 is 4.
When we divide both the numerator (16) and the denominator (20) by 4, we get:
16 ÷ 4 = 4
20 ÷ 4 = 5
Therefore, the equivalent fraction to 16/20 is 4/5.
The greatest common factor of 16 and 20 is 4.
When we divide both the numerator (16) and the denominator (20) by 4, we get:
16 ÷ 4 = 4
20 ÷ 4 = 5
Therefore, the equivalent fraction to 16/20 is 4/5.
Question 17 options:
Compare these fractions. Use <, >, or =.
fraction numerator 8 over denominator 9 end fractionBlank Space __________ fraction numerator 5 over denominator 9 end fraction
Compare these fractions. Use <, >, or =.
fraction numerator 8 over denominator 9 end fractionBlank Space __________ fraction numerator 5 over denominator 9 end fraction
To compare the fractions 8/9 and 5/9, we can compare their numerators since their denominators are the same.
The numerator of the first fraction, 8, is greater than the numerator of the second fraction, 5.
Therefore, we can conclude that 8/9 is greater than 5/9.
The correct comparison is: 8/9 > 5/9.
The numerator of the first fraction, 8, is greater than the numerator of the second fraction, 5.
Therefore, we can conclude that 8/9 is greater than 5/9.
The correct comparison is: 8/9 > 5/9.
Reduce this fraction to lowest terms.
fraction numerator 16 over denominator 32 end fraction
Select the correct answer.
Question 18 options:
Mathml image
Mathml image
Mathml image
Mathml image
fraction numerator 16 over denominator 32 end fraction
Select the correct answer.
Question 18 options:
Mathml image
Mathml image
Mathml image
Mathml image
To reduce the fraction 16/32 to its lowest terms, we need to find the greatest common factor (GCF) of the numerator and denominator, and then divide both the numerator and denominator by the GCF.
The GCF of 16 and 32 is 16.
When we divide both the numerator (16) and the denominator (32) by 16, we get:
16 ÷ 16 = 1
32 ÷ 16 = 2
Therefore, the fraction 16/32 can be reduced to 1/2.
The correct answer is:
1/2
The GCF of 16 and 32 is 16.
When we divide both the numerator (16) and the denominator (32) by 16, we get:
16 ÷ 16 = 1
32 ÷ 16 = 2
Therefore, the fraction 16/32 can be reduced to 1/2.
The correct answer is:
1/2
Solve the problem.
A leather jacket originally costs $150. If it goes on sale for 1 third off, how much will a customer save?
$Blank Space __________
A leather jacket originally costs $150. If it goes on sale for 1 third off, how much will a customer save?
$Blank Space __________
To calculate how much a customer will save, we need to find one-third of the original cost of the leather jacket.
One-third of $150 can be found by multiplying $150 by 1/3:
$150 * 1/3 = $50
Therefore, a customer will save $50 when the leather jacket goes on sale for one-third off.
One-third of $150 can be found by multiplying $150 by 1/3:
$150 * 1/3 = $50
Therefore, a customer will save $50 when the leather jacket goes on sale for one-third off.
Solve this problem. Reduce to lowest terms.
Jerome's rock band recorded 13 songs during an afternoon recording session. Each song took 1 over 6 of a side of a tape to record. How many sides were used during the session?
Select the correct answer.
Question 20 options:
Mathml image sides11
Mathml image sides22
Mathml image sides33
Mathml image sides44
Jerome's rock band recorded 13 songs during an afternoon recording session. Each song took 1 over 6 of a side of a tape to record. How many sides were used during the session?
Select the correct answer.
Question 20 options:
Mathml image sides11
Mathml image sides22
Mathml image sides33
Mathml image sides44
To find the number of sides used during the recording session, we need to divide the total number of songs by the fraction representing the length of each song.
There were 13 songs, and each song took 1/6 of a side of a tape to record.
To find the number of sides used, we can divide 13 by 1/6:
13 ÷ 1/6 = 13 * 6/1 = 78
Therefore, 78 sides were used during the recording session.
The correct answer is: 78 sides.
There were 13 songs, and each song took 1/6 of a side of a tape to record.
To find the number of sides used, we can divide 13 by 1/6:
13 ÷ 1/6 = 13 * 6/1 = 78
Therefore, 78 sides were used during the recording session.
The correct answer is: 78 sides.
Solve this problem. Reduce to lowest terms.
Jerome's rock band recorded 13 songs during an afternoon recording session. Each song took 1 over 6 of a side of a tape to record. How many sides were used during the session?
Select the correct answer.
Question 20 options:
Mathml image sides 1
Mathml image sides 2
Mathml image sides 3
Mathml image sides 4
Jerome's rock band recorded 13 songs during an afternoon recording session. Each song took 1 over 6 of a side of a tape to record. How many sides were used during the session?
Select the correct answer.
Question 20 options:
Mathml image sides 1
Mathml image sides 2
Mathml image sides 3
Mathml image sides 4
To find the number of sides used during the recording session, we need to divide the total number of songs by the fraction representing the length of each song.
There were 13 songs, and each song took 1/6 of a side of a tape to record.
To find the number of sides used, we can multiply 13 by 1/6:
13 * 1/6 = 13/6 = 2 and 1/6
Therefore, 2 and 1/6 sides were used during the recording session.
The correct answer is: 2 sides.
There were 13 songs, and each song took 1/6 of a side of a tape to record.
To find the number of sides used, we can multiply 13 by 1/6:
13 * 1/6 = 13/6 = 2 and 1/6
Therefore, 2 and 1/6 sides were used during the recording session.
The correct answer is: 2 sides.
Solve this problem. Reduce to lowest terms.
After work, Tami spends 1 half of an hour on the telephone, 5 over 8 of an hour exercising, and 3 over 4 of an hour doing laundry. What is the total amount of time Tami spends doing these activities?
Select the correct answer.
Question 21 options:
Mathml image hours
Mathml image hours
Mathml image hours
Mathml image hours
After work, Tami spends 1 half of an hour on the telephone, 5 over 8 of an hour exercising, and 3 over 4 of an hour doing laundry. What is the total amount of time Tami spends doing these activities?
Select the correct answer.
Question 21 options:
Mathml image hours
Mathml image hours
Mathml image hours
Mathml image hours
To find the total amount of time Tami spends on these activities, we need to add up the times spent on the telephone, exercising, and doing laundry.
Tami spends 1/2 hour on the telephone, 5/8 of an hour exercising, and 3/4 of an hour doing laundry.
To add these fractions, we need to find a common denominator. The least common denominator for 2, 8, and 4 is 8.
Converting the fractions to have a denominator of 8:
1/2 = 4/8
5/8 remains the same
3/4 = 6/8
Now, we can add the fractions:
4/8 + 5/8 + 6/8 = 15/8 = 1 and 7/8
Therefore, the total amount of time Tami spends doing these activities is 1 hour and 7/8 of an hour.
The correct answer is: 1 hours.
Tami spends 1/2 hour on the telephone, 5/8 of an hour exercising, and 3/4 of an hour doing laundry.
To add these fractions, we need to find a common denominator. The least common denominator for 2, 8, and 4 is 8.
Converting the fractions to have a denominator of 8:
1/2 = 4/8
5/8 remains the same
3/4 = 6/8
Now, we can add the fractions:
4/8 + 5/8 + 6/8 = 15/8 = 1 and 7/8
Therefore, the total amount of time Tami spends doing these activities is 1 hour and 7/8 of an hour.
The correct answer is: 1 hours.
Solve this problem. Reduce to lowest terms.
After work, Tami spends 1 half of an hour on the telephone, 5 over 8 of an hour exercising, and 3 over 4 of an hour doing laundry. What is the total amount of time Tami spends doing these activities?
Select the correct answer.
Question 21 options:
Mathml image hours 1
Mathml image hours 2
Mathml image hours 3
Mathml image hours 4
After work, Tami spends 1 half of an hour on the telephone, 5 over 8 of an hour exercising, and 3 over 4 of an hour doing laundry. What is the total amount of time Tami spends doing these activities?
Select the correct answer.
Question 21 options:
Mathml image hours 1
Mathml image hours 2
Mathml image hours 3
Mathml image hours 4
To find the total amount of time Tami spends on these activities, we need to add up the times spent on the telephone, exercising, and doing laundry.
Tami spends 1/2 hour on the telephone, 5/8 of an hour exercising, and 3/4 of an hour doing laundry.
To add these fractions, we need to find a common denominator. The least common denominator for 2, 8, and 4 is 8.
Converting the fractions to have a denominator of 8:
1/2 = 4/8
5/8 remains the same
3/4 = 6/8
Now, we can add the fractions:
4/8 + 5/8 + 6/8 = 15/8 = 1 and 7/8
Therefore, the total amount of time Tami spends doing these activities is 1 hour and 7/8 of an hour.
The correct answer is: 1 hours.
Tami spends 1/2 hour on the telephone, 5/8 of an hour exercising, and 3/4 of an hour doing laundry.
To add these fractions, we need to find a common denominator. The least common denominator for 2, 8, and 4 is 8.
Converting the fractions to have a denominator of 8:
1/2 = 4/8
5/8 remains the same
3/4 = 6/8
Now, we can add the fractions:
4/8 + 5/8 + 6/8 = 15/8 = 1 and 7/8
Therefore, the total amount of time Tami spends doing these activities is 1 hour and 7/8 of an hour.
The correct answer is: 1 hours.
Which ratio is equivalent to this one?
9/10
Select the correct answer.
Question 22 options:
19:20
16:20
18:20
9/10
Select the correct answer.
Question 22 options:
19:20
16:20
18:20
To find the equivalent ratio to 9/10, we can multiply the numerator and denominator by the same number to obtain another ratio that is equivalent.
Let's multiply 9/10 by 2:
(9/10) * 2 = 18/20
Therefore, the ratio 18:20 is equivalent to the ratio 9/10.
The correct answer is: 18:20.
Let's multiply 9/10 by 2:
(9/10) * 2 = 18/20
Therefore, the ratio 18:20 is equivalent to the ratio 9/10.
The correct answer is: 18:20.
Question 23 options:
Write this ratio another way.
120 over 150
Write this ratio another way.
120 over 150
To write the ratio 120 over 150 another way, we can simplify it by dividing both the numerator and denominator by their greatest common factor.
The greatest common factor of 120 and 150 is 30.
When we divide both the numerator (120) and the denominator (150) by 30, we get:
120 ÷ 30 = 4
150 ÷ 30 = 5
Therefore, the ratio 120 over 150 can be written as 4 over 5.
The correct answer is: 4 over 5.
The greatest common factor of 120 and 150 is 30.
When we divide both the numerator (120) and the denominator (150) by 30, we get:
120 ÷ 30 = 4
150 ÷ 30 = 5
Therefore, the ratio 120 over 150 can be written as 4 over 5.
The correct answer is: 4 over 5.
Find the unit rate.
Find the unit price for cheese that is sold in 12-ounce packages priced at $3.84.
$Blank Space __________ per ounce
Find the unit price for cheese that is sold in 12-ounce packages priced at $3.84.
$Blank Space __________ per ounce
To find the unit rate, we need to determine the cost per ounce of cheese.
The cost of a 12-ounce package of cheese is $3.84.
To find the cost per ounce, we divide the total cost by the number of ounces:
$3.84 / 12 ounces = $0.32 per ounce
Therefore, the unit rate, or unit price, for the cheese is $0.32 per ounce.
The cost of a 12-ounce package of cheese is $3.84.
To find the cost per ounce, we divide the total cost by the number of ounces:
$3.84 / 12 ounces = $0.32 per ounce
Therefore, the unit rate, or unit price, for the cheese is $0.32 per ounce.
Solve the problem.
A swimming pool is 6 meters wide and 10 meters long. Which fraction compares the pool's width to the pool's length?
Select the correct answer.
Question 25 options:
Mathml image 1
Mathml image 2
Mathml image 3
Mathml image 4
A swimming pool is 6 meters wide and 10 meters long. Which fraction compares the pool's width to the pool's length?
Select the correct answer.
Question 25 options:
Mathml image 1
Mathml image 2
Mathml image 3
Mathml image 4
To compare the pool's width to its length, we need to express the width as a fraction of the length.
The width of the swimming pool is 6 meters, and the length is 10 meters.
Therefore, the fraction that compares the pool's width (6 meters) to the pool's length (10 meters) is:
6/10
To simplify this fraction, we can divide both the numerator and denominator by their greatest common factor, which is 2:
(6/2)/(10/2) = 3/5
Therefore, the correct fraction that compares the pool's width to its length is 3/5.
The correct answer is: 3/5.
The width of the swimming pool is 6 meters, and the length is 10 meters.
Therefore, the fraction that compares the pool's width (6 meters) to the pool's length (10 meters) is:
6/10
To simplify this fraction, we can divide both the numerator and denominator by their greatest common factor, which is 2:
(6/2)/(10/2) = 3/5
Therefore, the correct fraction that compares the pool's width to its length is 3/5.
The correct answer is: 3/5.
Solve the problem.
In 2009, President Obama received an average of 25,000 letters per day. How many letters did he receive during the entire year?
In 2009, President Obama received an average of 25,000 letters per day. How many letters did he receive during the entire year?
To find the total number of letters President Obama received during the entire year, we need to multiply the average number of letters received per day by the total number of days in a year.
In 2009, there were 365 days in a year.
The average number of letters received per day is 25,000.
To find the total number of letters received during the year:
25,000 letters/day * 365 days/year = 9,125,000 letters
Therefore, President Obama received a total of 9,125,000 letters during the entire year of 2009.
In 2009, there were 365 days in a year.
The average number of letters received per day is 25,000.
To find the total number of letters received during the year:
25,000 letters/day * 365 days/year = 9,125,000 letters
Therefore, President Obama received a total of 9,125,000 letters during the entire year of 2009.
Phileas Fogg was the hero of Jules Verne's adventure novel Around the World in Eighty Days. The distance around the earth is about 25,000 miles. How far was Fogg able to travel in one day?
To calculate how far Fogg was able to travel in one day, we need to divide the total distance around the earth by the number of days it took to complete the journey.
In the novel, Fogg completed the journey in eighty days.
The total distance around the earth is about 25,000 miles.
To find how far Fogg was able to travel in one day:
25,000 miles / 80 days = 312.5 miles per day
Therefore, Fogg was able to travel approximately 312.5 miles in one day.
In the novel, Fogg completed the journey in eighty days.
The total distance around the earth is about 25,000 miles.
To find how far Fogg was able to travel in one day:
25,000 miles / 80 days = 312.5 miles per day
Therefore, Fogg was able to travel approximately 312.5 miles in one day.