Sure, let's go through each of these questions one at a time.
Question 11 To convert \(6 \frac{7}{15}\) to a decimal:
- Convert \( \frac{7}{15} \) to decimal by performing long division of 7 by 15.
- 15 goes into 70 (7.00) four times, since \( 15 \times 4 = 60 \). This leaves a remainder of \( 70 - 60 = 10 \).
- Bring down a 0, making it 100. 15 goes into 100 six times, since \( 15 \times 6 = 90 \). This leaves a remainder of \( 100 - 90 = 10 \).
- It would repeat the process leading to \( 0.46666...\)
Thus, \( \frac{7}{15} \approx 0.4666\).
So, \(6 \frac{7}{15} \approx 6.4666\).
The closest answer is: ≈6.47.
Question 12 Kimberly ran \( \frac{4}{5} \) of the track. The remaining part of the track can be calculated as follows:
- Calculate the remaining part: \( 1 - \frac{4}{5} = \frac{1}{5} \).
- Convert \( \frac{1}{5} \) to a percentage: \[ \frac{1}{5} \times 100 = 20% \]
Thus, the percentage of the track she ran at a slower pace is: 20%.
Question 13 To express \(90.5%\) as a decimal:
- Divide the percentage by 100: \[ 90.5% = \frac{90.5}{100} = 0.905 \]
Thus, \(90.5%\) written as a decimal is: 0.905.
Question 14 To find the rate of change in the plane's altitude:
- The plane descended \(4000\) feet in \(3.5\) minutes.
- Calculate the rate: \[ \text{Rate} = \frac{\text{change in altitude}}{\text{time}} = \frac{-4000\text{ feet}}{3.5\text{ minutes}} \approx -1142.8571428571429 \text{ feet/minute.} \]
- Rounded to the nearest hundredth: \[ \approx -1142.86 \text{ feet/minute.} \]
Thus, the rate of change in the plane's altitude is: −1142.86 feet/minute.
Question 15 To find the change in the amount of water in gallons in \(1\) minute:
- The pump removes \(250\) gallons in \(5\) minutes.
- Calculate the rate of change per minute: \[ \text{Rate} = \frac{-250 \text{ gallons}}{5 \text{ minutes}} = -50 \text{ gallons/minute.} \]
Thus, the change in the amount of water in gallons in \(1\) minute is: −50.
If you have more questions or need further assistance with any of these, just let me know!