Asked by lil Z
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Solve this problem.
A video tape will record 6 hours in the EP mode. Kyle has recorded 2 1 over 6 hours of a baseball game. He wants to record 3 3 over 4 hours more on the same tape. Can he do this?
Solve this problem.
A video tape will record 6 hours in the EP mode. Kyle has recorded 2 1 over 6 hours of a baseball game. He wants to record 3 3 over 4 hours more on the same tape. Can he do this?
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Answered by
GPT 3.5
To solve this problem, we need to determine if the remaining 3 3/4 hours can fit on the tape, given that 2 1/6 hours have already been recorded.
First, we need to find the total number of hours that have been recorded:
2 1/6 hours = (12 + 1) / 6 = 13/6 hours
Next, we add the total recorded hours to the additional hours Kyle wants to record:
13/6 + 3 3/4 = 13/6 + (12 + 3) / 4 = 13/6 + 15/4
To add these fractions, we need a common denominator:
In this case, the least common multiple of 6 and 4 is 12.
Converting 13/6 to a fraction with a denominator of 12:
13/6 = (13 * 2) / (6 * 2) = 26/12
Now we can add the fractions:
26/12 + 15/4 = (26 + 45) / 12 = 71/12
Therefore, a total of 71/12 hours have been recorded or are planned to be recorded.
Since the tape can record 6 hours in the EP mode, and 71/12 is less than 6, Kyle can still record the remaining 3 3/4 hours on the same tape.
First, we need to find the total number of hours that have been recorded:
2 1/6 hours = (12 + 1) / 6 = 13/6 hours
Next, we add the total recorded hours to the additional hours Kyle wants to record:
13/6 + 3 3/4 = 13/6 + (12 + 3) / 4 = 13/6 + 15/4
To add these fractions, we need a common denominator:
In this case, the least common multiple of 6 and 4 is 12.
Converting 13/6 to a fraction with a denominator of 12:
13/6 = (13 * 2) / (6 * 2) = 26/12
Now we can add the fractions:
26/12 + 15/4 = (26 + 45) / 12 = 71/12
Therefore, a total of 71/12 hours have been recorded or are planned to be recorded.
Since the tape can record 6 hours in the EP mode, and 71/12 is less than 6, Kyle can still record the remaining 3 3/4 hours on the same tape.
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