Question 1

Which of the following would be a situation with unbalanced forces?

a
Two people pulling on the same side of a wheelbarrow
b
A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c
Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d
Two people not touching a crate that is sitting stationary
Question 2
The acceleration due to gravity on Mars is 3.8 m/s2. How much would an object with a mass of 16 kg weigh on Mars?

a
4.2 N
b
61 N
c
96 N
d
16 N
Question 3
Balance the following the chemical equation:

a
1:2:1:1
b
1:1:1:2
c
1:1:2:1
d
2:1:1:1
Question 4
Which of the followng is Newton's Second Law?

a
An object in motion will stay in motion unless acted upon by an unbalanced outside force
b
Force = mass times acceleration
c
When one object puts a force on the another object, the second object puts a force back on the first, equal in magnitude and opposite in direction
Question 5
The table below shows the mass and velocity of four objects. Which object has the least inertia?

a
Y
b
Z
c
W
d
X
Question 6
Given the following nuclear reaction:



Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
a.86
b.88
c.228
d.Rn
e.Beta Decay
f.224
g.Th
h.220
i.84
j.Alpha Decay
k.Gamma Decay
l.Ra
m.90
Question 7
Trial Force (N) Acceleration (m/s^2)
1 10 N 2.5
2 12 3
3 22 5.5
Students are running an experiment in which they are measuring the acceleration after applying forces to a cart. Using the data above, what is the mass of the cart?

a
2 kg
b
4 kg
c
6 kg
d
8 kg
Question 8
A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?

a
0.4 kg
b
1.6 kg
c
2.4 kg
d
0.8 kg
Question 9
According to Newton's Third Law, if a sledgehammer hits a wall with a force of 1000 N, how much force does the wall hit the sledgehammer IF the sledgehammer does not go through the wall?

a
0 N
b
500 N
c
1000 N
d
- 1000 N
Question 10
Match the following terms to the correct element.

Column A
1.
Sulfur (S):
Sulfur (S)
2.
Sodium (Na):
Sodium (Na)
3.
Calcium (Ca):
Calcium (Ca)
4.
Carbon (C):
Carbon (C)
Column B
a.6 valence electrons
b.4th period
c.1 valence electron
d.4th group
Question 11
The table shows the acceleration due to gravity on four different planets. What planet is a person standing on if the person has a mass of 85.0 kg and weighs 305 N?

a
Mars
b
Venus
c
Earth
d
Mercury
Question 12
During an experiment in which you are investigating the acceleration changes due to force changes, what value must stay constant during these trials?

a
Force
b
Velocity
c
Acceleration
d
Mass
Question 13
As you are walking, you foot gets caught on an uneven piece of sidewalk and you trip and fall. Which of the following explains what is happening using Newton's Laws?

a
The sidewalk pushed you, causing a rapid force that made you fall
b
The sidewalk provided a force to stop your foot, but the top of your body was still moving which is what causes you to tip over
c
Your foot hit the sidewalk and provided a force on it, so the sidewalk will provide another force back on your foot, equal in magnitude but opposite in direct
d
Your foot pushes the sidewalk with such force that it causes the next piece of sidewalk to be uprooted, which makes your next step miss your footing
Question 14
The half-life for a 100-gram sample of radioactive element X is 5 days. How much of element X remains after 10 days have passed?

Starting amount Day5 Day10
100 g
a
25 g
b
50 g
c
75 g
d
100 g
Question 15
Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary

a
The force of gravity on the object is different if it is stationary or not.
b
The force of friction on the object is different if it is stationary or not
c
The force of the push on the object is different if it is stationary or not
d
The normal force on the object is different if it is stationary or not
Question 16
Looking at the periodic table, determine the number of valence electrons present in Phosphorous (P).

a
4 valence electrons
b
3 valence electrons
c
5 valence electrons
d
2 valence electrons
Question 17
Two rockets are being tested. Both rockets have the same mass. One rocket accelerates at a higher rate than another rocket. What could be true about the difference between the rockets?

a
One rocket has more fuel than the other
b
One rocket is more streamlined than the other
c
One rocket engine produces more force than the other
d
One rocket is more badly designed than the other
Question 18
Match each term to its correct description.

Column A
1.
Concentration:
Concentration
2.
Saturated Solution:
Saturated Solution
3.
Unsaturated Solution:
Unsaturated Solution
4.
Supersaturated Solution:
Supersaturated Solution
Column B
a.The amount of one substance in a certain volume of another substance.
b.A solution with as much dissolved solute as it can hold at a given temperature. No more solute can be dissolved.
c.A solution that holds less solute than is possible at a given temperature. More solute can dissolve.
d.A heated solution that holds more dissolved solute than is possible at a lower temperture.
Question 19
A block with a mass of 55 kg is pulled with a force of 220 N to the right. Assuming a frictionless surface, what will be the acceleration of the block?

a
9.8 m/s2

b
4.0 m/s2

c
0.25 m/s2

d
22 m/s2

Question 20
Which of the following phase changes involves a gas turning into a liquid?

a
Condensation
b
Boiling
c
Sublimation
d
Freezing
Question 21
Which of the following would be an example of Newton's Third Law forces?

a
A horse pulling a horse cart
b
A hammer striking a nail
c
A soccer ball bouncing off a wall
d
All of the above
Question 22
Before taking the Unit 6: Newton's Law Test, you were asked to review resources from the Unit 6: Newton's Law Resource Guide.

Below, list the two resources you reviewed and one thing you learned from each. At least two sentences per resource for your explanation.

**This is a required question - not bonus points. If you leave it unanswered, your test score will be impacted.**

Your answer:
Question 23
What are the primary forces that act upon a baseball and a bat during their collision with each other?

a
The force of ball on bat and the force of gravity on ball
b
The force of gravity on the bat and the force of friction on the ball
c
The normal force of the ball and the force of friction on the bat
d
The force of ball on bat and the force of the bat on ball
Question 24
An animal is walking forward. There is an applied force from the animal of 25 N to the right, a frictional force of 18 N to the left, a force of gravity of 65 N down and the animal is being pushed up by the ground with 65 N. What best describes the motion of the animal?

a
The animal will move to the left due to an unbalanced force on the left
b
The animal will move to the right due to an unbalanced force on the right
c
The animal will move down due to an unbalanced force down
d
The animal will move up due to an unbalanced force upward

9 answers

Here are the answers to your questions:

Question 1:
Answer: a
Explanation: Unbalanced forces occur when the forces acting on an object do not cancel each other out. In this case, two people pulling on the same side indicates an unbalanced force as they both exert force in the same direction.


Question 2:
Answer: b
Calculation: Weight = mass × gravitational acceleration = 16 kg × 3.8 m/s² = 60.8 N (approximately 61 N)


Question 3:
Answer: b
Explanation: Balancing a chemical equation typically requires finding coefficients that equalize the number of atoms for each element on both sides. The correct answer for an example would depend on the chemical equation provided.


Question 4:
Answer: b
Explanation: Newton's Second Law states that Force equals mass times acceleration (F = ma).


Question 5:
Answer: a
Explanation: The object with the least mass has the least inertia, which is the resistance to changes in motion.


Question 6:
Answers: 1. c (228); 2. g (Th); 3. d (Rn); 4. j (Alpha Decay)
Explanation: A specific nuclear reaction will determine these values, which usually require context or specific particles involved.


Question 7:
Answer: c
Calculation: According to Newton's second law, F = ma, so m = F/a. For trial 1, m = 10 N / 2.5 m/s² = 4 kg.


Question 8:
Answer: b
Calculation: To achieve acceleration at half the rate, A = F/m; if A is halved, m must double. Mass = Force / (acceleration/2) = 100N / (a/2) = 1.6 kg.


Question 9:
Answer: c
Explanation: According to Newton's Third Law, if a sledgehammer applies a force of 1000 N to the wall, the wall applies a force of 1000 N back toward the sledgehammer.


Question 10:
Answers: 1. d; 2. c; 3. b; 4. a
Explanation: Based on the periodic table, these terms relate to the number of valence electrons and atomic positions.


Question 11:
Answer: c
Calculation: Weight = mass × gravity, so 305 N = 85 kg × g. This gives g approximately equal to 3.59 m/s², which indicates Earth.


Question 12:
Answer: d
Explanation: The mass must remain constant in experiments investigating acceleration changes due to force changes.


Question 13:
Answer: b
Explanation: The sidewalk provided a force to stop the foot (static friction), while the body's upper portion continued moving forward, leading to the trip.


Question 14:
Answer: a
Calculation: After 10 days, which is two half-lives, 25 g remains (100 g → 50 g after 5 days, and then 50 g → 25 g after 10 days).


Question 15:
Answer: b
Explanation: The force of friction decreases once the object is in motion compared to when it is stationary.


Question 16:
Answer: c
Explanation: Phosphorus (P) has 5 valence electrons, as it sits in Group 15 of the periodic table.


Question 17:
Answer: c
Explanation: To achieve different acceleration rates while using the same mass, the engines must produce different amounts of force.


Question 18:
Answers: 1. a; 2. b; 3. c; 4. d
Explanation: These definitions are standard for describing solutions in chemistry.


Question 19:
Answer: b
Calculation: Using F = ma, m = F/a = 220 N / 55 kg = 4.0 m/s².


Question 20:
Answer: a
Explanation: The phase change from gas to liquid is known as condensation.


Question 21:
Answer: d
Explanation: All the options given represent examples of action-reaction force pairs, which is described by Newton's Third Law.


Question 22:
This question requires personal input and reflection on resources reviewed, which cannot be answered here.


Question 23:
Answer: d
Explanation: During the collision, the force exerted by the ball on the bat is met with an equal and opposite force exerted by the bat on the ball.


Question 24:
Answer: b
Explanation: The applied force to the right is greater than the frictional force to the left, resulting in net force and causing motion to the right.


Please let me know if you need additional explanations or depth on any of the questions!

question 3 image is _Na^2^O_+_CaBr^2--->_NaBr+_CaO

To balance the chemical equation given:

\[\text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow \text{NaBr} + \text{CaO}\]

Let's break it down:

  1. Count the number of each type of atom on both sides:

    • Reactants:

      • Na: 2 (from \(\text{Na}_2\text{O}\))
      • O: 1 (from \(\text{Na}_2\text{O}\))
      • Ca: 1 (from \(\text{CaBr}_2\))
      • Br: 2 (from \(\text{CaBr}_2\))
    • Products:

      • Na: 1 (from \(\text{NaBr}\))
      • Br: 1 (from \(\text{NaBr}\))
      • Ca: 1 (from \(\text{CaO}\))
      • O: 1 (from \(\text{CaO}\))
  2. Balance the sodium (Na) and bromine (Br) atoms by finding the lowest common multiple:

    • We have 2 Na in the reactants and only 1 Na in the products. Therefore, you need 2 \(\text{NaBr}\):
    • We have 2 Br in the reactants and only 1 Br in the \(\text{NaBr}\). Thus, we will use 2 \(\text{NaBr}\).
  3. The unbalanced equation now looks like this: \[\text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2\text{NaBr} + \text{CaO}\]

  4. Now the count looks like:

    • Reactants:

      • Na: 2
      • O: 1
      • Ca: 1
      • Br: 2
    • Products:

      • Na: 2 (from \(2\text{NaBr}\))
      • Br: 2 (from \(2\text{NaBr}\))
      • Ca: 1 (from \(\text{CaO}\))
      • O: 1 (from \(\text{CaO}\))

Both sides are now balanced!

Thus, the balanced equation is:

\[\text{Na}_2\text{O} + \text{CaBr}_2 \rightarrow 2\text{NaBr} + \text{CaO}\]

Final Answer for Question 3:

Answer: a (1:1:2:1)

Question 5 image: Object Mass Velocit(m/s)
W 16 2
X 15 3
Y 13 20
Z 2 30

To determine which object has the least inertia, we need to understand that inertia is largely dependent on mass. Inertia is the tendency of an object to resist changes in its state of motion. The greater the mass of an object, the greater its inertia.

Here are the objects with their masses:

  • W: 16 kg
  • X: 15 kg
  • Y: 13 kg
  • Z: 2 kg

From this list, we can see that:

  • Object W has a mass of 16 kg.
  • Object X has a mass of 15 kg.
  • Object Y has a mass of 13 kg.
  • Object Z has a mass of 2 kg.

Conclusion:

The object with the least mass, and thus the least inertia, is Object Z.

Final Answer for Question 5:

Answer: d (Z)

image for Question 6: 224/88Ra---->4/2He + A/Z X

To analyze the nuclear reaction given by the equation:

\[ ^{224}{88}\text{Ra} \rightarrow ,^{4}{2}\text{He} + ,^{A}_{Z}\text{X} \]

We will identify the values of A (atomic mass), Z (atomic number), symbol of the new atom (X), and type of decay.

Step 1: Determine A and Z

  1. The total mass number (A) must be conserved in the reaction.

    • On the left: \(224\) from \(^{224}_{88}\text{Ra}\)
    • On the right: \(4\) from \(^{4}_{2}\text{He}\) + A (mass number of X)

    The equation for mass numbers: \[ 224 = 4 + A \Rightarrow A = 224 - 4 = 220 \]

  2. The total atomic number (Z) must also be conserved.

    • On the left: \(88\) from \(^{224}_{88}\text{Ra}\)
    • On the right: \(2\) from \(^{4}_{2}\text{He}\) + Z (atomic number of X)

    The equation for atomic numbers: \[ 88 = 2 + Z \Rightarrow Z = 88 - 2 = 86 \]

Step 2: Determine the symbol of the new atom (X)

The new atom with atomic number 86 corresponds to Radon (Rn) from the periodic table. Thus, the symbol for the new atom is \(^{220}_{86}\text{Rn}\).

Step 3: Identify the type of decay

The reaction shows the emission of an \(^{4}_{2}\text{He}\) nucleus (an alpha particle), which means this is an alpha decay.

Summary:

  1. What is the atomic mass of the new atom? 220
  2. What is the atomic number of the new atom? 86
  3. What is the symbol of the new atom? Rn (Radon)
  4. What type of decay is demonstrated here? Alpha Decay

Final Answers for Question 6:

  1. Atomic Mass: 220 (f)
  2. Atomic Number: 86 (l)
  3. Symbol: Rn (d)
  4. Type of Decay: Alpha Decay (j)
question 11 image: Location Acceleration due to gravity(m/s^2)
Mercury 3.59
Venus 8.87
Earth 9.81
Mars 3.77

To determine which planet a person is standing on when their weight is 305 N and their mass is 85.0 kg, we first need to calculate the acceleration due to gravity (g) on that planet.

The weight (W) is given by the formula: \[ W = m \cdot g \] where:

  • \( W \) is weight in newtons (N),
  • \( m \) is mass in kilograms (kg),
  • \( g \) is the acceleration due to gravity in meters per second squared (m/s²).

Given:

  • Weight (\( W \)) = 305 N
  • Mass (\( m \)) = 85.0 kg

We can calculate \( g \):

\[ g = \frac{W}{m} = \frac{305 , \text{N}}{85.0 , \text{kg}} \approx 3.59 , \text{m/s}^2 \]

Now, let's compare this value with the provided acceleration numbers:

| Location | Acceleration due to gravity (m/s²) | |-----------|-------------------------------------| | Mercury | 3.59 | | Venus | 8.87 | | Earth | 9.81 | | Mars | 3.77 |

Analysis:

The calculated \( g \approx 3.59 , \text{m/s}^2 \) matches the acceleration due to gravity on Mercury.

Final Answer for Question 11:

Answer: Mercury

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