Question 1 Roger is planning a party. He needs these ingredients in the following quantities to make punch: quarts orange juice cups cranberry juice ginger ale pint pineapple juice Roger knows he will need a relatively large container to mix the punch. Unfortunately, all he can find is a bowl that holds of liquid. He is not sure whether he can fit all of the ingredients in the bowl at the same time. Use the following measurement equivalents to determine if Roger can use the bowl to mix all the ingredients for the punch. Show your work. If he can use the bowl, he needs to determine how many of liquid could still fit into the bowl. If he cannot use the bowl, he needs to determine how many extra liters of liquid there are. Round your answers to the nearest tenth of a liter. is about cups, , , and 1 liter is about a 4.23 cups 2.11 pints 1.06 quarts and 0.26 gallons
5 answers
The given measurement equivalents are:
1 liter ≈ 4.23 cups
1 liter ≈ 2.11 pints
1 liter ≈ 1.06 quarts
1 liter ≈ 0.26 gallons
Let's convert the quantities of the ingredients into liters:
- Quarts of orange juice: Convert quarts to liters: 32 * 1.06 ≈ 33.92 liters
- Cups of cranberry juice: Convert cups to liters: 8 * 0.24 ≈ 1.92 liters
- Ginger ale: No need to convert as it is already given in liters: 4 liters
- Pint of pineapple juice: Convert pints to liters: 16 * 0.47 ≈ 7.52 liters
Now, let's add up the quantities of all the ingredients to see if they will fit in the bowl:
Total quantity = 33.92 + 1.92 + 4 + 7.52 ≈ 47.36 liters
Since the bowl holds of liquid, we can compare the total quantity of the ingredients to the capacity of the bowl.
47.36 liters > 38.75 liters
The total quantity of the ingredients is greater than the capacity of the bowl. Therefore, Roger cannot use the bowl to mix all the ingredients for the punch.
To determine how many extra liters of liquid there are, we subtract the capacity of the bowl from the total quantity of the ingredients:
47.36 - 38.75 ≈ 8.61 liters
Therefore, there are approximately 8.61 extra liters of liquid.