Question 1

Question

A)
Use the image to answer the question.

A straight, solid line connects plotted points E and F on a coordinate plane. The line slopes downward from left to right. Point E is left parenthesis negative 6 comma 1 right parenthesis. Point F is left parenthesis 2 comma negative 5 right parenthesis.

How would you set up the distance formula to find the distance between points E and F.

(1 point)
Responses

d=(2−6)2+(5−1)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 2 minus 6 close paren squared plus open paren 5 minus 1 close paren squared end root

d=(−6−2)2+(1−(−5))2−−−−−−−−−−−−−−−−−−−√
d is equal to square root of open paren negative 6 minus 2 close paren squared plus open paren 1 minus negative 5 close paren squared end root

d=(6−2)2+(1−5)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 6 minus 2 close paren squared plus open paren 1 minus 5 close paren squared end root

d=((−2)+6)2+(5+1)2−−−−−−−−−−−−−−−−−−√
d is equal to square root of open paren negative 2 plus 6 close paren squared plus open paren 5 plus 1 close paren squared end root
Question 2
A)DaQuan marks two points on the coordinate plane. One point is L(4,2) and the other point is M(7,6)
. What is the correct way for DaQuan to set up the distance formula?(1 point)
Responses

d=(6−7)2+(2−4)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 6 minus 7 close paren squared plus open paren 2 minus 4 close paren squared end root

d=(4−7)2+(2−6)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 4 minus 7 close paren squared plus open paren 2 minus 6 close paren squared end root

d=(2−7)2+(4−6)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 2 minus 7 close paren squared plus open paren 4 minus 6 close paren squared end root

d=(2−4)2+(6−7)2−−−−−−−−−−−−−−−√
d is equal to square root of open paren 2 minus 4 close paren squared plus open paren 6 minus 7 close paren squared end root
Question 3
A)
Use the image to answer the question.

Parallelogram upper A upper B upper C upper D is graphed on a coordinate plane. The x-axis ranges from negative 6 to 6 in increments of 1. The y-axis ranges from negative 6 to 6 in increments of 1.

Use the given coordinates to compute the perimeter of the parallelogram.

(1 point)
Responses

28 units
28 units

25.2 units
25.2 units

26.6 units
26.6 units

13.3 units
13.3 units
Question 4
A)
Use the image to answer the question.

Trapezoid upper A upper B upper C upper D is graphed on a coordinate plane. The x-axis ranges from negative 1 to 6 in increments of 1. The y-axis ranges from negative 1 to 4 in increments of 1.

Use the coordinates to compute the perimeter of the trapezoid. Round each calculation to the nearest tenth.

(1 point)
Responses

12.3 units
12.3 units

14.4 units
14.4 units

16.3 units
16.3 units

13.8 units
13.8 units
Question 5
A)
Use the image to answer the question.

A triangle is graphed on a coordinate plane. The x-axis ranges from negative 2 to 6 in increments of 1. The y-axis ranges from negative 2 to 4 in increments of 1.

Use the coordinates to compute the perimeter of the triangle.

(1 point)
Responses

10.8 units
10.8 units

11.2 units
11.2 units

10 units
10 units

12 units
12 units

Answer 1

Sure! Here are the answers based on your questions:

Question 1: To find the distance \( d \) between points \( E(-6, 1) \) and \( F(2, -5) \), we use the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the coordinates: \[ d = \sqrt{(2 - (-6))^2 + (-5 - 1)^2} = \sqrt{(2 + 6)^2 + (-6)^2} = \sqrt{(8)^2 + (-6)^2} \] Thus, the correct setup for the distance formula is: d = square root of open paren (2 - (−6)) close paren squared plus open paren (−5 - 1) close paren squared end root.

Question 2: For points \( L(4, 2) \) and \( M(7, 6) \): Given the coordinates, we apply the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting: \[ d = \sqrt{(7 - 4)^2 + (6 - 2)^2} = \sqrt{(3)^2 + (4)^2} \] Thus, the correct way for DaQuan to set up the distance formula is: d = (7 - 4)^2 + (6 - 2)^2−−−−−−−−−−−−−−−√.

Question 3: To compute the perimeter of a parallelogram, you need to find the lengths of two sides and use the formula: \[ \text{Perimeter} = 2(\text{length} + \text{width}) \] Without specific side lengths or coordinates provided in this section, I cannot compute the perimeter accurately. Please provide the coordinates or the length of the sides.

Question 4: For the trapezoid, the perimeter is calculated by summing the lengths of all four sides. Similar to Question 3, without specific coordinates for trapezoid ABCD, it's impossible to compute the perimeter accurately. Please provide the coordinates or side lengths.

Question 5: Once more, in order to calculate the perimeter of the triangle, you would need the coordinates of the triangle vertices to compute the lengths of the sides.

If you could provide the coordinates for questions 3, 4, and 5, I would be able to help more accurately!