Let's break down each question and find the correct answers.
Question 1
Problem: The Boston Ballet charges a flat rate of $50.00 plus $15.00 per ticket. The school wants to take a class of 25 students to see The Nutcracker.
Equation: Let \( x \) be the number of students (25) and \( y \) be the total cost. \[ y = 50 + 15x \]
Calculating the total cost: \[ y = 50 + 15(25) \] \[ y = 50 + 375 \] \[ y = 425 \]
Response: $425.00
Question 2
Problem: The school soccer team is raising funds by selling chips at $2.50 per bag and wants to raise $1,000.
Equation: Let \( b \) be the number of bags sold. \[ 2.50b = 1000 \]
Calculating the number of bags needed: \[ b = \frac{1000}{2.50} \] \[ b = 400 \]
Response: 400 bags
Question 3
Problem: Identify an example that represents a discrete data constraint with viable solutions.
Discrete data is countable, like the number of something (e.g., tests passed).
Response: number of tests passed
Question 4
Problem: Identify which options could use both intercepts to produce viable solutions.
Options that can produce both x and y intercepts generally involve two quantitative variables.
Response: (number of nominations, number of awards)
Question 5
Problem: Cindy wants to spend her $50.00 on robotics kits ($10 each) and chemistry sets ($8 each).
Let \( x \) be the number of chemistry sets, and \( y \) be the number of robotics kits.
Equation: \[ 8x + 10y = 50 \]
Testing each option:
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(−5, 9): \[ 8(-5) + 10(9) = -40 + 90 = 50 \] (Viable solution, but negative not possible)
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(5, 1): \[ 8(5) + 10(1) = 40 + 10 = 50 \] (Viable solution)
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(3, 2.6): \[ 8(3) + 10(2.6) = 24 + 26 = 50 \] (Invalid as y should be an integer)
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(0, 5): \[ 8(0) + 10(5) = 0 + 50 = 50 \] (Viable solution)
Response: (5, 1)
Summary of Responses:
- $425.00
- 400 bags
- number of tests passed
- (number of nominations, number of awards)
- (5, 1)